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# Last year, the number of months in which natalie went over

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Manager
Joined: 03 Jun 2003
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Last year, the number of months in which natalie went over [#permalink]  11 Jul 2003, 07:10
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(N/A)

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100% (01:54) correct 0% (00:00) wrong based on 1 sessions
I find this question, give it a try

data sufficiency
in some months last year, natalie, a sales representative at
SmithKline & Beecham, went over $60000 in sales. in how many months last year did she do so? 1. last year, the number of months in which natalie went over$60000 was 8 months more than the number of
months in which she did not.
2. last year, the number of months in which natalie went
below $60000 was 1/5 the number of months in which she did not. SVP Joined: 03 Feb 2003 Posts: 1609 Followers: 6 Kudos [?]: 75 [0], given: 0 [#permalink] 11 Jul 2003, 08:30 X is the number of months when Natalie exceeds 60K. 12–X is the number of months when she does not. (1) X=8+12–X, so X=10; thus, OK (2) (12–X)=X/5, so X=10; thus, OK again Finally, it is D. The trick is that you know how many months there are in a year. Manager Joined: 03 Jun 2003 Posts: 84 Location: Uruguay Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] 11 Jul 2003, 10:41 As I said, it is tricky, D is wrong SVP Joined: 03 Feb 2003 Posts: 1609 Followers: 6 Kudos [?]: 75 [0], given: 0 [#permalink] 11 Jul 2003, 10:52 over 60K means at least 60001 USD. below 60K means at best 59999 USD NOT below means 60K or more In this case we have not two variables but three 2 seems to be out A? Manager Joined: 02 Jul 2003 Posts: 58 Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] 11 Jul 2003, 10:54 I'm new but i'll give it a shot- B A is wrong because she could have had 2 months of 60k in production. Manager Joined: 25 Jun 2003 Posts: 95 Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] 11 Jul 2003, 11:32 There are 3 possibilities in every month i. Sales > 60000, ii. Sales = 60000 0r iii. sales < 60000 From 1 : x = y + 8 , but x+y not necessarily equal to 12 From 2 : y = x/5. So answer is C. But interestingly, x + y ends up in 12 ???? ( x = 10, y = 2 ) _________________ Brainless GMAT Instructor Joined: 07 Jul 2003 Posts: 770 Location: New York NY 10024 Schools: Haas, MFE; Anderson, MBA; USC, MSEE Followers: 13 Kudos [?]: 52 [0], given: 0 [#permalink] 11 Jul 2003, 18:36 A is correct. 1) You can solve for number of month > 60K which is the question asked. 2) You can solve for number of month not < 60K but no info on whether it equal to or greater than. Given the context of the question, IMO, it is reasonable to assume that we are talking about 12 months (we are talking about "last year"). _________________ Best, AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993 Manager Joined: 18 Jun 2003 Posts: 141 Location: Hockeytown Followers: 2 Kudos [?]: 16 [0], given: 0 [#permalink] 11 Jul 2003, 19:19 I would agree about (A) but this is more like a RC than a math Q Manager Joined: 08 Apr 2003 Posts: 149 Followers: 1 Kudos [?]: 8 [0], given: 0 [#permalink] 12 Jul 2003, 04:08 I guess An should be B. B gives what is the NUmber of months = 1/5(Number of mhs she did not). That's wht the problem says ... Manager Joined: 05 May 2003 Posts: 68 Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] 12 Jul 2003, 07:03 E. From 2. we get no of months in which natalie went below$60000 = 2. that means remaining 10 months either she == 60000 or > 60000.
From 1. no of months > 60000 = 8 + no of months <= 60000. we cannont find this information.
SVP
Joined: 03 Feb 2003
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it is time to post the official answer. Probably, there are no more answers left.
Manager
Joined: 03 Jun 2003
Posts: 84
Location: Uruguay
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Kudos [?]: 0 [0], given: 0

As AkamaiBrah explained it
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