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Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 4 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt?

For Li : R= 4, Time = t => Distance = 4t

For Wal: R= 6, Time = t-2 => Distance = 6(t-2)

one can easily solve this question with this information.

My question is : how Time for Wal is " t-2" ?? According to question, lets say, Li left home at 4pm, two hours later Wal left his house, it means 6pm. wouldn't it be ( t+2) in algebraic way.

Re: words translation [#permalink]
11 Aug 2011, 12:07

1

This post received KUDOS

Answer is 24.

My way of solving such questions is altogether different. I used diagrams and divided the distance in fractions of 4 and 6. Anyway.

Answering your question, they have taken t-2 because W left his lous 2 hours after L started. Means L walked for 2 more hours. Dont confuse it with actual time of the day.

Simplyfying it,

- Keep the first 2 hours aside for sometime. L walked 8 miles in those 2 hours. So distance left is 48 - 8 = 40 miles - L walks 4 miles per hour and W walks 6 miles per hour. The meet when they have walked for similar time. Let the time be T

putting this in equation, 4T + 6T = 40 so T = 4. Tells us, both walked for 4 hours when they met.

So L walked for 4*4 = 16 miles . Adding his initial 8 miles, he waked for 24 miles in total.

Re: words translation [#permalink]
11 Aug 2011, 22:25

1

This post received KUDOS

shrive555 wrote:

Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 4 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt?

For Li : R= 4, Time = t => Distance = 4t

For Wal: R= 6, Time = t-2 => Distance = 6(t-2)

one can easily solve this question with this information.

My question is : how Time for Wal is " t-2" ?? According to question, lets say, Li left home at 4pm, two hours later Wal left his house, it means 6pm. wouldn't it be ( t+2) in algebraic way.

Thanks

t is not the "time" in literal sense. It is the time taken Walt. As Walt started 2 hours late, the time he takes for the travel is 2 hours less than Lionel's. Thus, (t-2)

e.g. A starts at 1:00PM and walks B starts at 4:00PM, runs swiftly, and catches A at 5:00PM

By 5:00 PM: A would have walked for t hours i.e. 4 hours B would have run for (t-3) hours i.e. (4-3)=1 hour

Re: words translation [#permalink]
15 Aug 2011, 21:15

Expert's post

shrive555 wrote:

Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 4 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt?

I think piyatiwari and fluke have already explained you what the variable t stands for. Now let's see how to solve this question without any variables.

For the first two hrs, only Lionel was walking at a speed of 4 miles/hr. So he covered 8 miles in that time. Now the distance between him and Walt is 40 miles. Now, Lionel is walking toward Walt at 4 miles/hr and Walt is running toward Lionel at 6 miles/hr. So they are covering 10 miles every hour. They will together cover 40 miles in 4 hrs. In these 4 hrs, Lionel walked 4*4 = 16 miles. He also walked 8 miles in the first two hrs. Hence he covered a total of 16+8 = 24 miles