Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 4 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt?
For Li : R= 4, Time = t => Distance = 4t
For Wal: R= 6, Time = t-2 => Distance = 6(t-2)
one can easily solve this question with this information.
My question is : how Time for Wal is " t-2" ?? According to question, lets say, Li left home at 4pm, two hours later Wal left his house, it means 6pm. wouldn't it be ( t+2) in algebraic way.
t is not the "time" in literal sense. It is the time taken Walt. As Walt started 2 hours late, the time he takes for the travel is 2 hours less than Lionel's. Thus, (t-2)
A starts at 1:00PM and walks
B starts at 4:00PM, runs swiftly, and catches A at 5:00PM
By 5:00 PM:
A would have walked for t hours i.e. 4 hours
B would have run for (t-3) hours i.e. (4-3)=1 hour
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