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Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 08:43
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What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT
[Reveal] Spoiler: OA

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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 08:54
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


area_{square}=side^2=\frac{diagonal^2}{2}: so A to be the answer either option A should read 50 instead of 5 or diagonal should be \sqrt{10} instead of 10.
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Senior Manager
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 09:02
Bunuel wrote:
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


area_{square}=side^2=\frac{diagonal^2}{2}: so A to be the answer either option A should read 50 instead of 5 or diagonal should be \sqrt{10} instead of 10.


Yes. Answer quite clearly should be 50.

Does this OE make sense to you:
From the relationship that exists in a right triangle, we see that the sides of the square
must equal the square root of 5. Thus the area of the square is 5
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 09:07
gmatpapa wrote:
Bunuel wrote:
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


area_{square}=side^2=\frac{diagonal^2}{2}: so A to be the answer either option A should read 50 instead of 5 or diagonal should be \sqrt{10} instead of 10.


Yes. Answer quite clearly should be 50.

Does this OE make sense to you:
From the relationship that exists in a right triangle, we see that the sides of the square
must equal the square root of 5. Thus the area of the square is 5


As OE says that side=\sqrt{5} then there must be the second case I suggested: diagonal should be \sqrt{10} instead of 10.
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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!


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Senior Manager
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Status: ready to boMBArd
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Concentration: Entrepreneurship, Strategy
Schools: Kellogg 1YR '13 (S), Johnson '14 (WL), ISB (D), Carlson (A)
GMAT 1: 710 Q48 V40
WE: Project Management (Manufacturing)
Followers: 10

Kudos [?]: 31 [0], given: 67

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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 09:15
Yep. Quite correct as diagonal = sqrt2*side. So side will be \frac{sqrt10}{sqrt2}= sqrt 5. And area will be side^2= 5.
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 05:03
i did a bit different - x^2+x^2 = 10^2
x=squrt2*5
x^2 = 2*25 = 50
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Status: ready to boMBArd
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Schools: Kellogg 1YR '13 (S), Johnson '14 (WL), ISB (D), Carlson (A)
GMAT 1: 710 Q48 V40
WE: Project Management (Manufacturing)
Followers: 10

Kudos [?]: 31 [0], given: 67

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Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 06:01
144144 wrote:
i did a bit different - x^2+x^2 = 10^2
x=squrt2*5
x^2 = 2*25 = 50


Its essentially the same thing if you look at it. Diagonal= sqrt2*side is arrived using the same formula that you have used. (Pythagoras theorem)
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 10:23
ye, i noticed it after i posted. thanks.
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Re: Area: Do you see a correct answer choice here?   [#permalink] 05 Feb 2011, 10:23
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