Find all School-related info fast with the new School-Specific MBA Forum

It is currently 25 Jul 2014, 03:22

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In the rectangular coordinate system, are the points (a,

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Manager
Manager
User avatar
Joined: 01 Aug 2008
Posts: 118
Followers: 1

Kudos [?]: 13 [0], given: 2

In the rectangular coordinate system, are the points (a, [#permalink] New post 02 Jun 2009, 03:05
5
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

57% (02:18) correct 43% (01:08) wrong based on 133 sessions
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) \frac{a}{b} =\frac{c}{d}

(2) \sqrt{a^2} + \sqrt{b^2} = \sqrt{c^2} + \sqrt{d^2}

[Reveal] Spoiler: Answer:
C

_________________

==============================================
Do not answer without sharing the reasoning behind ur choice
-----------------------------------------------------------
Working on my weakness : GMAT Verbal
------------------------------------------------------------
Ask:
Why, What, How, When, Where, Who
==============================================

Expert Post
14 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18737
Followers: 3243

Kudos [?]: 22383 [14] , given: 2616

Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 12:53
14
This post received
KUDOS
Expert's post
tinki wrote:
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses


In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

Distance between the point A (x,y) and the origin can be found by the formula: D=\sqrt{x^2+y^2}.

So we are asked whether \sqrt{a^2+b^2}=\sqrt{c^2+d^2}? Or whether a^2+b^2=c^2+d^2?

(1) \frac{a}{b}=\frac{c}{d} --> a=cx and b=dx, for some non-zero x. Not sufficient.

(2) \sqrt{a^2}+\sqrt{b^2}=\sqrt{c^2} +\sqrt{d^2} --> |a|+|b|=|c|+|d|. Not sufficient.

(1)+(2) From (1) a=cx and b=dx, substitute this in (2): |cx|+|dx|=|c|+|d| --> |x|(|c|+|d|)=|c|+|d| --> |x|=1 (another solution |c|+|d|=0 is not possible as d in (1) given in denominator and can not be zero, so d\neq{0} --> |c|+|d|>0) --> now, as |x|=1 and a=cx and b=dx, then |a|=|c| and |b|=|d| --> square this equations: a^2=c^2 and b^2=d^2 --> add them: a^2+b^2=c^2+d^2. Sufficient.

Answer: C.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

4 KUDOS received
Manager
Manager
User avatar
Joined: 01 Aug 2008
Posts: 118
Followers: 1

Kudos [?]: 13 [4] , given: 2

Re: distance in rectangular coordinate system [#permalink] New post 02 Jun 2009, 20:44
4
This post received
KUDOS
goldeneagle94 wrote:
amolsk11 wrote:
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

This singnifies that the sign combination on both sides of = is the same.
i.e. if one of the numbers on LHS is -ve , one of the numbers on RHS has to -ve as well.
However since a,b / c,d can take any value , INSUFFICIENT.

(2) (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2)
Since we do not know anything about signs of a,b / c,d - INSUFFICIENT.


Using 1 and 2 together ,
using (1) the second statement drills down to
a+b=c+d (the sign combination on both sides of = is the same.)

Since a/b=c/d and a+b=c+d , (a, b) and (c, d) equidistant from the origin and infact represent the same point.


Is there a way we can derive, using these two equations, that the two points are equidistant ?



For the derivation part:

a^2 + b^2 = c^2 + d^2

b^2[(a^2/b^2) + 1] = d^2[(c^2/d^2 +1)] --------> 1

from I

a/b = c/d
squaring both sides
a^2/b^2 = c^2/d^2
putting above in 1 and simplifying

b^2[(c^2/d^2) + 1] = d^2[(c^2/d^2 +1)]
simplifying

b^2 = d^2
or |b| = |d|
=> |a| = |c|

therefore points are equidistant from (0,0) or Origin.
_________________

==============================================
Do not answer without sharing the reasoning behind ur choice
-----------------------------------------------------------
Working on my weakness : GMAT Verbal
------------------------------------------------------------
Ask:
Why, What, How, When, Where, Who
==============================================

2 KUDOS received
Director
Director
avatar
Status: -=GMAT Jedi=-
Joined: 04 Jan 2011
Posts: 741
Location: Kochi, India
Schools: ISB
WE 1: Engineer - Larsen & Toubro, ECC Division
WE 2: Faculty - T.I.M.E.
Followers: 32

Kudos [?]: 122 [2] , given: 66

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 12:06
2
This post received
KUDOS
tinki wrote:
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses

a/b=c/d <---- Equation 1

|a|+|b|=|c|+|d|

Add 1 to both sides of Equation 1

(a+b)/b=(c+d)/d

Now a+b=c+d => 1/b=1/d

Thus, b=d
Similarly,
b/a=d/c
Adding 1 to both sides of above equation:
(b+a)/a=(d+c)/c
a+b=d+c => 1/a=1/c
Therefore a=c
_________________

Mission: Be a force of good and make a positive difference to every life I touch!

From 650 to 710 to 750 - My Tryst With GMAT [Experience Thread]

1 KUDOS received
Intern
Intern
avatar
Joined: 27 May 2009
Posts: 6
Followers: 0

Kudos [?]: 1 [1] , given: 0

Re: distance in rectangular coordinate system [#permalink] New post 03 Jun 2009, 06:24
1
This post received
KUDOS
in order for the points to be equidistant

a2 + b2 = c2+ d2 -----> eq X

1--> insufficent (has already been discussed)
2--> insufficent (has already been discussed)

combining both,
equation 2 can be written as a+b = c+d

eq1 a/b = c/d
a+b/b = c+d/d, from eq 1 from b=d ----3

similarly, b/a = d/c, a+b/a = d+c/c from eq 1 a = c ----4


plug in values of a, b in eq X... it satifies.

Hence points are equidistant. Answer is C
1 KUDOS received
Manager
Manager
avatar
Joined: 17 Aug 2010
Posts: 90
Followers: 1

Kudos [?]: 5 [1] , given: 22

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 13:27
1
This post received
KUDOS
Bunuel wrote:
tinki wrote:
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses


In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

Distance between the point A (x,y) and the origin can be found by the formula: D=\sqrt{x^2+y^2}.

So we are asked whether \sqrt{a^2+b^2}=\sqrt{c^2+d^2}? Or whether a^2+b^2=c^2+d^2?

(1) \frac{a}{b}=\frac{c}{d} --> a=cx and b=dx, for some non-zero x. Not sufficient.

(2) \sqrt{a^2}+\sqrt{b^2}=\sqrt{c^2} +\sqrt{d^2} --> |a|+|b|=|c|+|d|. Not sufficient.

(1)+(2) From (1) a=cx and b=dx, substitute this in (2): |cx|+|dx|=|c|+|d| --> |x|(|c|+|d|)=|c|+|d| --> |x|=1 (another solution |c|+|d|=0 is not possible as d in (1) given in denominator and can not be zero, so d\neq{0} --> |c|+|d|>0) --> now, as |x|=1 and a=cx and b=dx, then |a|=|c| and |b|=|d| --> square this equations: a^2=c^2 and b^2=d^2 --> add them: a^2+b^2=c^2+d^2. Sufficient.

Answer: C.


your explanation is great as always ! thaaanks
+ Kudo
CEO
CEO
User avatar
Joined: 29 Aug 2007
Posts: 2501
Followers: 51

Kudos [?]: 484 [0], given: 19

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 02 Jun 2009, 06:44
mbaMission wrote:
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d
(2) (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2)


(1) If a/b = c/d, a and b could be 100 and c and d could be 1 or a, b, c and d could be 1. NSF.

(2) If (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2), then a+b = c+d. In this case, if a = 9 and b = 1, and c =d=5, a+b = c+d is true. but they have different distance.NSF.

From 1 and 2, a must be equal to c and b must be equal to d. So Suff.

Thats C.
_________________

Verbal: new-to-the-verbal-forum-please-read-this-first-77546.html
Math: new-to-the-math-forum-please-read-this-first-77764.html
Gmat: everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

Senior Manager
Senior Manager
User avatar
Joined: 16 Jan 2009
Posts: 362
Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Followers: 2

Kudos [?]: 65 [0], given: 16

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 02 Jun 2009, 11:13
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

This singnifies that the sign combination on both sides of = is the same.
i.e. if one of the numbers on LHS is -ve , one of the numbers on RHS has to -ve as well.
However since a,b / c,d can take any value , INSUFFICIENT.

(2) (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2)
Since we do not know anything about signs of a,b / c,d - INSUFFICIENT.


Using 1 and 2 together ,
using (1) the second statement drills down to
a+b=c+d (the sign combination on both sides of = is the same.)

Since a/b=c/d and a+b=c+d , (a, b) and (c, d) equidistant from the origin and infact represent the same point.
_________________

Lahoosaher

Manager
Manager
User avatar
Joined: 08 Feb 2009
Posts: 147
Schools: Anderson
Followers: 3

Kudos [?]: 31 [0], given: 3

Re: distance in rectangular coordinate system [#permalink] New post 02 Jun 2009, 17:23
amolsk11 wrote:
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

This singnifies that the sign combination on both sides of = is the same.
i.e. if one of the numbers on LHS is -ve , one of the numbers on RHS has to -ve as well.
However since a,b / c,d can take any value , INSUFFICIENT.

(2) (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2)
Since we do not know anything about signs of a,b / c,d - INSUFFICIENT.


Using 1 and 2 together ,
using (1) the second statement drills down to
a+b=c+d (the sign combination on both sides of = is the same.)

Since a/b=c/d and a+b=c+d , (a, b) and (c, d) equidistant from the origin and infact represent the same point.


Is there a way we can derive, using these two equations, that the two points are equidistant ?
Manager
Manager
avatar
Joined: 11 Aug 2008
Posts: 162
Followers: 1

Kudos [?]: 35 [0], given: 8

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 08 Jun 2009, 22:29
GMAT TIGER wrote:
mbaMission wrote:
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d
(2) (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2)


(1) If a/b = c/d, a and b could be 100 and c and d could be 1 or a, b, c and d could be 1. NSF.

(2) If (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2), then a+b = c+d. In this case, if a = 9 and b = 1, and c =d=5, a+b = c+d is true. but they have different distance.NSF.

From 1 and 2, a must be equal to c and b must be equal to d. So Suff.

Thats C.

why from a^2 + b^2= c^2 + d^2 => a+b=c+d ?
Manager
Manager
User avatar
Joined: 22 Jul 2009
Posts: 192
Followers: 4

Kudos [?]: 186 [0], given: 18

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 19 Aug 2009, 18:29
ngoctraiden1905 wrote:
why from a^2 + b^2= c^2 + d^2 => a+b=c+d ?


That is not so.

What other posters said is that from (a^2)^(1/2) + (b^2)^(1/2) = (c^2)^(1/2) + (d^2)^(1/2) => a+b=c+d

That is actually incorrect. Should be |a|+|b|=|c|+|d|.
Manager
Manager
avatar
Joined: 17 Aug 2010
Posts: 90
Followers: 1

Kudos [?]: 5 [0], given: 22

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 11:45
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses
Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18737
Followers: 3243

Kudos [?]: 22383 [0], given: 2616

Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 13:32
Expert's post
AmrithS wrote:
tinki wrote:
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses

a/b=c/d <---- Equation 1

|a|+|b|=|c|+|d|

Add 1 to both sides of Equation 1

(a+b)/b=(c+d)/d

Now a+b=c+d => 1/b=1/d

Thus, b=d
Similarly,
b/a=d/c
Adding 1 to both sides of above equation:
(b+a)/a=(d+c)/c
a+b=d+c => 1/a=1/c
Therefore a=c


No that's not correct.

|a|+|b|=|c|+|d| doesn't mean that a+b=c+d (consider a=b=1 and c=d=-1). So from |a|+|b|=|c|+|d| and a/b=c/d we can not derive that a=c and b=d. What we can derive is that |a|=|c| and |b|=|d|. Refer to my post above for complete solution.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Director
Director
avatar
Status: -=GMAT Jedi=-
Joined: 04 Jan 2011
Posts: 741
Location: Kochi, India
Schools: ISB
WE 1: Engineer - Larsen & Toubro, ECC Division
WE 2: Faculty - T.I.M.E.
Followers: 32

Kudos [?]: 122 [0], given: 66

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 05 Feb 2011, 19:36
Sorry! My Bad :)
Bunuel is right! Thanks for the explanation man....
_________________

Mission: Be a force of good and make a positive difference to every life I touch!

From 650 to 710 to 750 - My Tryst With GMAT [Experience Thread]

Senior Manager
Senior Manager
avatar
Joined: 21 Mar 2010
Posts: 316
Followers: 5

Kudos [?]: 20 [0], given: 33

GMAT Tests User
Re: distance in rectangular coordinate system [#permalink] New post 19 Feb 2011, 18:12
Entwistle wrote:
tinki wrote:
Official explanation says:
"If we know the proportion of a to b is the same as c to d and that |a| + |b| = |c| + |d|, then it must be the case that |a| = |c| and |b| = |d| ?

could someone elaborate how we are supposed to know |a| = |c| and |b| = |d|? a bit vague statement for me

thanks for responses

a/b=c/d <---- Equation 1

|a|+|b|=|c|+|d|

Add 1 to both sides of Equation 1

(a+b)/b=(c+d)/d

Now a+b=c+d => 1/b=1/d

Thus, b=d
Similarly,
b/a=d/c
Adding 1 to both sides of above equation:
(b+a)/a=(d+c)/c
a+b=d+c => 1/a=1/c
Therefore a=c



I liked your explanation, of course Bunuel was as helpful as ever too.
Intern
Intern
avatar
Joined: 20 Dec 2011
Posts: 11
Location: United States
GMAT 1: 760 Q50 V42
Followers: 0

Kudos [?]: 9 [0], given: 0

Re: In the rectangular coordinate system, are the points (a, [#permalink] New post 21 Dec 2011, 09:34
Here's a simpler solution......

We need to prove a^2 + d^2 = c^2 + b^2

Simpler way is to rearrange statement 2 viz. |a| + |b| = |c| + |d| as
1. |a| - |d| = |c| - |b| and then square both sides. We get -
2. a^2 + d^2 - 2*|a|*|d| = c^2 + b^2 - 2*|c|*|b|.

Since ad = bc as per statement 1,

3. |ad| = |bc| => |a|.|d| = |b|.|c| (Rule -> Abs of Product = Product of Abs)

So we can cancel the third term out from both sides of equation 2. to get the desired equation

HTH
Intern
Intern
avatar
Joined: 17 Mar 2011
Posts: 10
Followers: 0

Kudos [?]: 0 [0], given: 2

Reviews Badge
Re: In the rectangular coordinate system, are the points (a, [#permalink] New post 27 Jul 2012, 20:49
Hi there, i was just wondering if the way i do it is correct!

Statement 1: insuff
Statement 2 : |a|+|b|=|c|+|d|

Our goal is to prove that a^2 + b^2 = c^2 + d^2

(1+2)

Square both sides in stmt 2.

We have a^2 + b^2 + 2|a||b| = c^2 + d^2 + 2|c||d| ----------- *
From one we know that a/b=c/d, therefore their LHS=RHS and therefore, this condition would allow us to cancel out 2|a||b| from LHS and 2|c||d| from equation *.

Please tell me that i am correct! =)

Reagan
Intern
Intern
avatar
Joined: 11 Jul 2012
Posts: 27
Followers: 0

Kudos [?]: 4 [0], given: 1

Re: In the rectangular coordinate system, are the points (a, [#permalink] New post 08 Aug 2012, 02:22
reagan wrote:
Hi there, i was just wondering if the way i do it is correct!

Statement 1: insuff
Statement 2 : |a|+|b|=|c|+|d|

Our goal is to prove that a^2 + b^2 = c^2 + d^2

(1+2)

Square both sides in stmt 2.

We have a^2 + b^2 + 2|a||b| = c^2 + d^2 + 2|c||d| ----------- *
From one we know that a/b=c/d, therefore their LHS=RHS and therefore, this condition would allow us to cancel out 2|a||b| from LHS and 2|c||d| from equation *.

Please tell me that i am correct! =)

Reagan


Absolutely, I found this approach much better. Infact I am wondering why we are targetting absolute values in the equation.

(a+b)^2 = a^2+b^2+2ab [no absolute |a|, |b| needed]

From
1) we know ab = cd
2) we know a + b = c + d. and hence (a+b)^2 = (c+d)^2

Combining 1) & 2) we can very well see that a^2+b^2 = c^2+d^2
SVP
SVP
User avatar
Joined: 09 Sep 2013
Posts: 1731
Followers: 165

Kudos [?]: 33 [0], given: 0

Premium Member
Re: In the rectangular coordinate system, are the points (a, [#permalink] New post 01 Nov 2013, 03:40
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Intern
Intern
avatar
Joined: 23 Feb 2014
Posts: 36
GMAT 1: 560 Q41 V26
GMAT 2: 610 Q46 V28
Followers: 0

Kudos [?]: 2 [0], given: 15

Premium Member CAT Tests
Re: In the rectangular coordinate system, are the points (a, [#permalink] New post 25 May 2014, 07:13
Awesome discussion and solution analysis.

Thank you all!
Re: In the rectangular coordinate system, are the points (a,   [#permalink] 25 May 2014, 07:13
    Similar topics Author Replies Last post
Similar
Topics:
3 Experts publish their posts in the topic In the rectangular coordinate system Point O has coordinates imhimanshu 7 11 Jun 2013, 06:56
7 Experts publish their posts in the topic In a rectangular coordinate system, point A has coordinates Financier 14 20 Aug 2010, 13:30
In a rectangular coordinate system, there are three points hadzamir 1 02 Dec 2005, 06:57
In the rectangular coordinate system are the points (r, s) Seyi 1 08 Dec 2004, 15:41
In the rectangular coordinate system, are the points (r,s) ceg2002 1 24 Aug 2004, 14:27
Display posts from previous: Sort by

In the rectangular coordinate system, are the points (a,

  Question banks Downloads My Bookmarks Reviews Important topics  

Go to page    1   2    Next  [ 22 posts ] 



GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.