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M03 #24 DS Question [#permalink]
 09 Dec 2008, 16:09
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Is N^x even? 1. N is even 2. x^2-3x+2 = 0 * Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient * Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient * BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient * EACH statement ALONE is sufficient * Statements (1) and (2) TOGETHER are NOT sufficient Source: GMAT Club Tests - hardest GMAT questions
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Re: M03 DS Question [#permalink]
09 Dec 2008, 16:13
I think the answer is A.
But the OA is C.
An even number raised to any power is always even.
(2) provides the power as 1 or 2. But doesn't give anything about the base.
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Re: M03 DS Question [#permalink]
09 Dec 2008, 17:15
Quote: An even number raised to any power is always even. The power needs to be a positive integer for this statement to be true. You need the second equation to find that x is a positive integer.
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Re: M03 DS Question [#permalink]
09 Dec 2008, 23:04
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topmbaseeker wrote: Is N^x even?
1. N is even
2. x^2-3x+2 = 0
(C) 2008 GMAT Club - m03#24
* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient has to be C. 1: n = lets say 2 but x could be -1, 0, 0.5, 2. Then in all cases, n^x is not an even. so nsff.. 2: x = 1 or 2 but what is n? nsf. therefore, C.
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 05:24
Good question. Even i picked A on the first go. However, after seeing the answer, C made sense 
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 10:34
Hi,
C is the correct option because even if N is even N^x can be odd.
Consider for example N = 4
N^0 = 4^0 =1 which is odd
If we consider the second statement then we come to know that x can be either 1 or 2.
So from 1 and 2 both we can answer the question properly hence the solution for this is C.
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 12:33
i made the same mistake...i chose A....well that was tricky one...
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 15:35
Easy one..!!
C.
Both Stmt together solve the purpose.
Since to be even depends upon both N & x .we need to have both to conclude.
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 18:59
How did you get x=1 or X=2 from x2 -3X+2 = 0.
Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ?
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Re: M03 #24 DS Question [#permalink]
15 Jul 2010, 19:13
x2-3x+2=0
x2-x-2x+2=0
x(x-1) -2(x-1)=0
(x-2)(x-1)=0
=>x=1 or x=2
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Re: M03 #24 DS Question [#permalink]
16 Jul 2010, 00:28
not worthy of hardest questions set!
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No Execuse..
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Re: M03 #24 DS Question [#permalink]
16 Jul 2010, 06:48
Francois wrote: How did you get x=1 or X=2 from x2 -3X+2 = 0.
Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ? Hi, You need to know the basics of quadratic equation to solve. Try searching for Crammers Rule.
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Re: M03 #24 DS Question [#permalink]
19 Jul 2011, 05:46
I chose (A) at first as well. We don't know whether X is an integer or not, that made sense for me. So the correct answer is (C) as far as we learn that N is a positive integer.
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Re: M03 #24 DS Question [#permalink]
20 Jul 2011, 11:09
bit of a trick question
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Re: M03 #24 DS Question [#permalink]
23 Jul 2011, 20:01
good one..thanks for the explanation
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Re: M03 #24 DS Question [#permalink]
23 Jul 2012, 06:27
Made the same mistake .. once the clock hits 2 mins i lose calm
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Re: M03 #24 DS Question [#permalink]
23 Jul 2012, 07:48
Quite easy...ans C
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Re: M03 #24 DS Question [#permalink]
23 Jul 2012, 14:15
Nice trick question . Easy but missed it. Accounted for the negative numbers as well but missed the fact that for a simple (2^-1) it fails.  Good one.
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Re: M03 #24 DS Question
[#permalink]
23 Jul 2012, 14:15
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