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Answer will be E. I is insufficient because X = (1,2) U (3,infinity) and II is also not sufficient as X> 1, in this cas X can be 1.5,2,2.5 etc. combining I and II is not sufficient.

Consider 1st statement; (x-3)(x-2)(x-1)>0 This is true in 4 cases: Case 1: (x-3), (x-2), (x-1) all are > 0, which is possible if x>3 {x-3 > 0} Case 2: (x-3) > 0 and (x-2) and (x-1) < 0 which is not possible if x>3 Case 3: (x-3) and (x-2)< 0 and (x-1) > 0 which is possible if 1<x<2 Case 4: (x-3) and (x-1)< 0 and (x-2) > 0 which is not possible if x>2 [since x-1 can not be negative for x>2] This gives two possible answers from Case 1 (x>3) & case 3 (1<x<2). Therefore, this statement is NOT SUFFICIENT

Consider 2nd statement; x>1 That does not tell us if x>3 or x<3, x could be 1.5, 2, 2.5 etc...Hence, this is NOT SUFFICIENT

Combining 1st and 2nd statement does not give us exact value of x. Hence, the answer should be E

1) Both X=4 and X=1.5 satisfy (X-3)(X-2)(X-1)>0 -> insufficient 2) Clearly insufficient Combine 2 stats: still cannot, using the same examples as in 1)