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Re: Is quadrilateral ABCD a rhombus? [#permalink]
23a2012 wrote:
Why the above question has the answer E while the below question has the answer D?Where I can understand the difference between option B in the both question from Bunuel clarification but I did not see any difference in the option A between both qouestion so why option A is incorrect in the above question while it is correct in the below question?

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD


In the Kite as Bunuel explained notice that only one diagonal is bisected while the other is not while in rhombus/square both diagonals are bisected(since, square is a special case of rhombus). So, (1) is sufficient. As far (2) is concerned it has to be rhombus any quadrilateral having equal sides is a rhombus & hence, (2) is sufficient as well.
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Re: Is quadrilateral ABCD a rhombus? [#permalink]
honchos wrote:
Is quadrilateral ABCD a rhombus?

(1) AC is perpendicular to BD
(2) AB + CD = BC +AD

M11-05


Statement 1

No because this could simply be a rectangle- a rectangle in which the lengths are bigger than the widths

Insuff

Statement 2

Actually no- this statement is trying to trick you into assuming that all four sides are equal, in which case the statement would be sufficient. However, a kite can fit this criteria and so

Insuff
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Re: Is quadrilateral ABCD a rhombus? [#permalink]
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honchos wrote:
Is quadrilateral ABCD a rhombus?

(1) AC is perpendicular to BD
(2) AB + CD = BC +AD

M11-05


Bunuel what what is the difference between saying "AC is perpendicular to BD" v "AC and BD are perpendicular bisectors"

In other problems the statement is a rhombus if it is known that "AC and BD are perpendicular bisectors."
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Re: Is quadrilateral ABCD a rhombus? [#permalink]
Expert Reply
Nunuboy1994 wrote:
honchos wrote:
Is quadrilateral ABCD a rhombus?

(1) AC is perpendicular to BD
(2) AB + CD = BC +AD

M11-05


Bunuel what what is the difference between saying "AC is perpendicular to BD" v "AC and BD are perpendicular bisectors"

In other problems the statement is a rhombus if it is known that "AC and BD are perpendicular bisectors."



A perpendicular bisector is a line which cuts a line segment into two equal parts at 90°.

A line segment bisector is a line which cuts a line segment into two equal parts.

A line is perpendicular to another if it meets or crosses it at right angles (90°).
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Re: Is quadrilateral ABCD a rhombus? [#permalink]
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Re: Is quadrilateral ABCD a rhombus? [#permalink]
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