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M17Q5

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Current Student
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Joined: 27 Jun 2012
Posts: 418
Concentration: Strategy, Finance
Followers: 44

Kudos [?]: 369 [0], given: 182

Re: M17Q5 [#permalink] New post 18 Jan 2013, 16:36
The sum of infinite geometric progression with common ratio |r|<1 , is sum=\frac{b}{1-r}, where b is the first term.

Hence here sum = \frac{1}{2}/(1-\frac{1}{2}) = 1

Hence choice(D) is the answer!
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Re: M17Q5   [#permalink] 18 Jan 2013, 16:36
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