Can someone please explain how to solved there kinds of problems. Im having a tough time with mixture problems.
Some part of the 50% soultion of acid was replaced with the equal amount of 30% solution of acid. As a result, 40% solution of acid was obtained. What part of the original solution was replaced ?
Solution A: acid = 50%, Volume = A-B
Solution B: acid = 30%, Volume = B
Solution C: acid = 40%, Volume = A
50*(A-B) + 30*B = 40*A
50A - 40A = 50B - 30B
10A = 20B
B/A = 1/2