Mixture Problems Made Easy

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Manager

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Re: Mixture Problems Made Easy [#permalink]

06 Dec 2010, 11:07

Thanks for sharing

Manager

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Re: Mixture Problems Made Easy [#permalink]

17 Mar 2011, 00:34

thanks for sharing

Manager

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Re: Mixture Problems Made Easy [#permalink]

18 Mar 2011, 00:16

Always have trouble with mixture problems, thanks!

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Re: Mixture Problems Made Easy [#permalink]

20 Mar 2011, 17:35

great post! thanks

Intern

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Re: Mixture Problems Made Easy [#permalink]

20 Jul 2011, 21:32

Thanks alot for this, its very helpful

Manager

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Re: Mixture Problems Made Easy [#permalink]

27 Jul 2011, 22:18

KillerSquirrel wrote:

Mixture problems made Easy

solving mixture problems fast ! - (30 day money back guarantee :wink:

)

see attachment

Thanks

:-D

Awesome material Bro.

Thanks a lot for sharing. Now I am a lot more confident on these mixture problems.

-Raghu
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Re: Mixture Problems Made Easy [#permalink]

16 Aug 2011, 00:08

good one...!!!!
Could someone please explain the 3rd and 5th example in detail.?

Manager

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Re: Mixture Problems Made Easy [#permalink]

07 Nov 2011, 03:01

tkp wrote:

gr8 post!

but can anyone show me how to solve this problem , with the method given here

Question: 10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?

Could anyone answer this question?
Do we need to know the weight of sand or clay?
My approach is:
Based on this new method:

30% ------------------------ X%
--------------50%
(X-50)% -------------------- 20%

so in new mixture
\frac{20}{100}=\frac{weight}{10}

weight = 2

I'm not confident about my answer at all. is it right?

Manager

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Re: Mixture Problems Made Easy [#permalink]

07 Nov 2011, 03:02

Thank you. it's a perfect approach. but could you plz elaborate the last example in PDF file? i didn't understand that one.
Thanks

Manager

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Re: Mixture Problems Made Easy [#permalink]

29 Feb 2012, 16:06

I'm struggling using this method... may be because I'm not very strong with ratios!

Intern

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Re: Mixture Problems Made Easy [#permalink]

24 Apr 2012, 00:45

Hi everyone,

I, too, am struggling with understanding the first example on this pdf.

I believe I understand the diagram, but where I'm struggling is the final step: so it appears that the 30 corresponds to the 15%, and the 50 corresponds with the 5%. So I understood this ratio to mean the 30% solution compared to the 50% solution has a ratio of 15:5 or 3:1. Based on this, I thought the answer should be 7.5 (but I know logically it should actually be 2.5). Would appreciate any insight on this.

Intern

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Re: Mixture Problems Made Easy [#permalink]

05 Aug 2012, 07:22

Great post, thanks.

Re: Mixture Problems Made Easy [#permalink] 05 Aug 2012, 07:22

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Mixture Problems Made Easy

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