Mixture Problems Made Easy : GMAT Quantitative Section
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# Mixture Problems Made Easy

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Mixture Problems Made Easy [#permalink]

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02 Aug 2007, 14:24
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Mixture problems made Easy

solving mixture problems fast ! - (30 day money back guarantee )

see attachment

Thanks

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Last edited by KillerSquirrel on 30 Aug 2007, 23:25, edited 2 times in total.
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02 Aug 2007, 14:33
thanks for sharing
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02 Aug 2007, 15:08
Thank you for posting that! It's much easier than the way I was solving mixtures.
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04 Aug 2007, 04:46
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You are all welcome !

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07 Aug 2007, 11:37
KillerSquirrel wrote:
You are all welcome !

Great contribution, thank you KillerSquirrel
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07 Aug 2007, 11:43
awesome page! thanks!
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07 Aug 2007, 13:15
Excellent page, makes these things appear a lot simple!
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Wow, that was awesome. Do you have anything like that for... [#permalink]

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09 Aug 2007, 02:56
inequalities and ultimate values? These 2 have been a huge issue for me.

Thanks for posting that - it's going to help a lot!
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06 Mar 2010, 09:44
So far this questions gave me a hard time!!Great tool!!Thanks
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Re: Mixture Problems Made Easy [#permalink]

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09 Jul 2010, 03:40
once you get the hang of these questions and practice a few they are pretty straightforward. The trick is trying to work out what the question is getting at!
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16 Jul 2010, 06:17
one of the best posts on the website - thanks a lot. This makes these problems like child's play. I wouldn't be surprised if some company TMs this technique if hasn't already.
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Re: Mixture Problems Made Easy [#permalink]

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16 Jul 2010, 18:08
Thanks for sharing... this is very helpful....
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19 Jul 2010, 20:06
Thanks for the wonderful method.
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23 Jul 2010, 14:19
Thanks good job!

Posted from my mobile device
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25 Jul 2010, 07:33
thanks
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25 Jul 2010, 20:17
thanks. This was a great help.
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25 Jul 2010, 20:18
thanks. This was a great help.
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26 Jul 2010, 03:58
great quick process - thanks
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Re: Mixture Problems Made Easy [#permalink]

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23 Sep 2010, 14:45
Quick question.

In the Example 5, the explanation says that the volume of the new solution is x/2. If one amount of solution replaces the same amount, how is the volume of the new solution cut in half? If I take out 1 liter of solution and replace it with 1 liter of another solution, my overall volume stays the same. Could someone please explain the assumption that the volume is x/2.

Thanks!
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28 Oct 2010, 06:54
gr8 post!

but can anyone show me how to solve this problem , with the method given here

Question: 10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?
Re: Mixture Problems Made Easy   [#permalink] 28 Oct 2010, 06:54

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# Mixture Problems Made Easy

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