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Of the goose eggs laid at a certain pond, 2/3 hatched and 3/

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Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 30 Jan 2014, 00:55
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The Official Guide For GMAT® Quantitative Review, 2ND Edition

Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?

(A) 280
(B) 400
(C) 540
(D) 600
(E) 840

Problem Solving
Question: 69
Category: Arithmetic Operations with rational numbers
Page: 70
Difficulty: 600


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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 30 Jan 2014, 00:55
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SOLUTION

Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?

(A) 280
(B) 400
(C) 540
(D) 600
(E) 840

Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.

Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.

120 geese survived the first year:

1/5*(total) = 120 --> (total) = 600.

Answer: D.
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 30 Jan 2014, 02:01
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Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 f the geese that hatched from those eggs survived the first month.Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?

(A) 280
(B) 400
(C) 540
(D) 600
(E) 840


Sol: Plugging in answer choices is best bet
Start with C and lets see..
540 eggs laid ----> 2/3 hatached so 540*2/3 = 360 and 3/4 of these eggs survived the first month so 3/4*360=270 survived and out of these 2/5 survived the first year. so 270*2/5=96...But is given that 120 geese survived so no of eggs laid must be more than 540 so

Lets take D and check 6000----> 2/3h hatched (400) of these 3/4 survived first month is 300 and out 300 2.5 survied first year which 2/5*300=120----> same as stated in the Question.

So Ans D

600 level is okay
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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 30 Jan 2014, 02:04
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choice D.
Let the total geese be x
Given:x*(2/3)*(3/4)*(2/5)=120
Therefore,x/5=120
x=600
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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 01 Feb 2014, 07:56
Expert's post
SOLUTION

Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?

(A) 280
(B) 400
(C) 540
(D) 600
(E) 840

Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.

Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.

120 geese survived the first year:

1/5*(total) = 120 --> (total) = 600.

Answer: D.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 05 Dec 2014, 00:25
I used a bit different approach. The total must be LCM of 3, 4, and 5 or else, fraction won't make to 120. This means whatever the total is, it must be multiple of 60. I started with 540 and landed with 112 instead of 120 and I went on to mark 600. Is this approach correct?

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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/ [#permalink] New post 05 Dec 2014, 01:11
Let the goose eggs laid at pond = x

Total hatched \(= \frac{2x}{3}\)

Survived in 1st month \(= \frac{2x}{3} * \frac{3}{4} = \frac{x}{2}\)

Not surviving 1st year \(= \frac{x}{2} * \frac{3}{5} = \frac{3x}{10}\)

Surviving 1st year \(= \frac{5x}{10} - \frac{3x}{10} = \frac{2x}{10}\)

Given that \(\frac{2x}{10} = 120\)

x = 120*5 = 600

Answer = D
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Re: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/   [#permalink] 05 Dec 2014, 01:11
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