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27 Jun 2023, 01:31
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
95% (01:03) correct
5%
(01:51)
wrong
based on 55
sessions
History
Date
Time
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Not Attempted Yet
A tightrope approximately 320 m long is suspended between two poles. During a performance, a break occurs in the line. Assume that the line has an equal chance of breaking anywhere along its length. What is the probability that the break happened in the first 50 meters of the rope?
A. 27/32
B. 1/2
C. 5/32
D. 5/27
E. 2/3
A. 27/32
B. 1/2
C. 5/32
D. 5/27
E. 2/3
27 Jun 2023, 02:48
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first 50 mtrs
total 320
50/320 ; 5/32
option C
total 320
50/320 ; 5/32
option C
Bunuel
27 Jun 2023, 04:27
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The probability that the break happened in the first 50 meters of the rope can be determined by dividing the length of the first 50 meters (50 m) by the total length of the rope (320 m).
Probability = Length of first 50 meters / Total length of the rope
Probability = 50 m / 320 m
Probability = 5/32
Therefore, the correct option is C. 5/32.
Probability = Length of first 50 meters / Total length of the rope
Probability = 50 m / 320 m
Probability = 5/32
Therefore, the correct option is C. 5/32.
