chetan2u
At Rocket Brown Elementary School there are 150 students and three sports teams – hockey, tennis, and football. Rocket Brown students are allowed to participate in as many of the three sports as they like or to abstain from participation completely. At the beginning of the semester, 40 students choose to play hockey, 50 choose to play tennis and 90 choose to play football, while 70 decide to play exactly two sports simultaneously.
In the table, select a value that would be the greatest number of students who could choose to play all three sports and the greatest number of students who could choose to play no sports at all. Make only two selections, one in each column.
With 96% incorrect out of first 24 timers taken, the question may seem to be very tough, but can be simplified by Venn Diagram.
Otherwise, the solution would be
Different components: Only h, Only t, Only f, Only h&t, Only h&f, Only t&f, all three, None
Given:Total = Only h + Only t + Only f + Only h&t + Only h&f + Only t&f+ all three + None = 150
H = Only h + Only h&t + Only h&f + all three = 40
T = Only t + Only h&t + Only t&f + all three = 50
F = Only f + Only f&t + Only h&f + all three = 90
Only h&t + Only h&f + Only t&f = 70
So, just re arranging the total....
H+T+F=40+50+90 = 180
(Only h + Only h&t + Only h&f + all three) + (Only t + Only h&t + Only t&f + all three) + (Only f + Only f&t + Only h&f + all three) = 180
Only h + Only t + Only f + 2(Only h&t + Only h&f + Only t&f) + 3(all three) = 180
(Only h + Only t + Only f + Only h&t + Only h&f + Only t&f + all three) + (Only h&t + Only h&f + Only t&f) + 2*all three = 180
(150 - None) + 70 + 2*all three = 180
None - 2* all three = 40
As we increase None, 'all three will also increase'. Thus, for All \(three_{max}\), we will get \(None_{max}\)
As 90 play football and 90 is largest set of people given, the none could be all remaining, that is 150-90 = 60.
So 60 - 2*all three = 40 or all three = 10.
Note: If someone wants to know all the parts. Since everything is a part of F, all parts that do not contain F are 0.
Total = Only h + Only t + Only f + Only h&t + Only h&f + Only t&f+ all three + None = 150
H = Only h + Only h&t + Only h&f + all three = 0 + 0 + Only h&f + 10 = 40........Only h&f = 30
T = Only t + Only h&t + Only t&f + all three = 0 + 0 + Only t&f + 10 = 50........Only t&f = 40
F = Only f + Only f&t + Only h&f + all three = Only f + 30 + 40 + 10 = 90........Only f = 10