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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
chetan2u and karishma B

Where is it mentioned that we need to find "greatest number of students who could choose to play all three sports and the greatest number of students who could choose to play no sports at all" in a single case.

Can't there be 2 cases:

Case 1: Greatest number of students who could choose to play all three sports.

In this case I will say that there will be 0 players with not playing in all three sports.
So, the greatest number students who could choose to play all three sports will come to be 40


Case 2: Greatest number of students who could choose to play no sports at all" in a single case.

In this case, I will maximize the overlapping and the answer would be 60 for players playing no sports.

It isn't clear from the question that we want to maximize both in 1 case. Am I sounding correct?­
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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
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arkaja11
chetan2u and karishma B

Where is it mentioned that we need to find "greatest number of students who could choose to play all three sports and the greatest number of students who could choose to play no sports at all" in a single case.

Can't there be 2 cases:

Case 1: Greatest number of students who could choose to play all three sports.

In this case I will say that there will be 0 players with not playing in all three sports.
So, the greatest number students who could choose to play all three sports will come to be 40


Case 2: Greatest number of students who could choose to play no sports at all" in a single case.

In this case, I will maximize the overlapping and the answer would be 60 for players playing no sports.

It isn't clear from the question that we want to maximize both in 1 case. Am I sounding correct?­

You are correct on the point that the two cases need not be under the same scenario. But the above two cases are interconnected.

However, when you solve you have to ensure that the total are 150. If 40 are in the ‘all three’ overlap, then 70 in exactly two does not fit in. This would mean someone should have at least 40+70 or 110.

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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
chetan2u
arkaja11
chetan2u and karishma B

Where is it mentioned that we need to find "greatest number of students who could choose to play all three sports and the greatest number of students who could choose to play no sports at all" in a single case.

Can't there be 2 cases:

Case 1: Greatest number of students who could choose to play all three sports.

In this case I will say that there will be 0 players with not playing in all three sports.
So, the greatest number students who could choose to play all three sports will come to be 40


Case 2: Greatest number of students who could choose to play no sports at all" in a single case.

In this case, I will maximize the overlapping and the answer would be 60 for players playing no sports.

It isn't clear from the question that we want to maximize both in 1 case. Am I sounding correct?­
You are correct on the point that the two cases need not be under the same scenario. But the above two cases are interconnected.

However, when you solve you have to ensure that the total are 150. If 40 are in the ‘all three’ overlap, then 70 in exactly two does not fit in. This would mean someone should have at least 40+70 or 110.

Posted from my mobile device
­
Got it.

By maximizing the overlapping, I was suggesting of maximizing the overlap with the constraints (70 of them playing exactly 2). Basically, similar to what you have suggested in the solution. So, I would have reached the same answer, i.e 60.
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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
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Let's leverage the formula for overlapping sets with the EXACTLY 2 condition:

Total=A+B+C−(sum of EXACTLY 2−group overlaps)−2∗(all three)+Neither

150 = 40 + 50 + 90 - (70) - 2*all three + neither
40= -2*all three + neither
test 10 for all three and 60 for neither

40 = -2*10 + 60
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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
Let's leverage the formula for overlapping sets with the EXACTLY 2 condition:

Total=A+B+C−(sum of EXACTLY 2−group overlaps)−2∗(all three)+Neither

150 = 40 + 50 + 90 - (70) - 2*all three + neither
40= -2*all three + neither --> 40 = -2x + y

now we are told to maximize both values, let's try to substitute:

x=0 --- y=40 
x=10 --- y=60

x=20 --- y=80
x=40 --- y=120
x=50 --- y=140
x=60 --- y=160­

only the ones in red fit with the solutions options and the second one provide higher values for both x & y 
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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
­#sport/student         #student        #sport
1                             a                   a
2                             70                 140
3                             c                   3c
Total                                             180   

a + 70 + c + n = 150
(n = number of students who choose to play no sports at all)

a + 140 + 3c = 180
a + 3c = 40
3c <= 40
c <= 13.3
From the answer choices => c = 10


n is highest when the overlap is the largest
The number of students playing exactly two sports is alreayd given
=> We can only maximizing n by maximizing c (those playing all three)

max c = 10
=> a = 10
=> n = 150 - 10 - 70 - 10 = 60



             
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Re: ­At Rocket Brown Elementary School there are 150 students and [#permalink]
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