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PS: Exponents (m06q07)

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Re: PS: Exponents (m06q07) [#permalink] New post 05 Apr 2013, 23:00
I did the same way as other guys.

2^98 = 256L + N
2^98 = 2^8 x L + N
L = 2^90
So N = 0

A is correct.


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Re: PS: Exponents (m06q07)   [#permalink] 05 Apr 2013, 23:00
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PS: Exponents (m06q07)

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