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Director
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PS-numbers [#permalink] New post 24 Jun 2007, 21:02
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Manager
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 [#permalink] New post 24 Jun 2007, 21:09
I think the correct answer is A
My reasoning,
X^4 + y^4 = 100, so the greatest value of X would be when Y is minimized, so assume Y = 0;
So X^4 = 100
=> X^2 = 10
=> X = Sqrt(10)
=> so x > 3 and X <4
now, looking at the answer choices, if we assume Y has some value, we can safely assume that X is between 0 and 3

What is OA; i am torn between A or B, but if I had to guess, I would choose A
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 [#permalink] New post 24 Jun 2007, 21:20
saurster wrote:
I think the correct answer is A
My reasoning,
X^4 + y^4 = 100, so the greatest value of X would be when Y is minimized, so assume Y = 0;
So X^4 = 100
=> X^2 = 10
=> X = Sqrt(10)
=> so x > 3 and X <4
now, looking at the answer choices, if we assume Y has some value, we can safely assume that X is between 0 and 3

What is OA; i am torn between A or B, but if I had to guess, I would choose A


I did so, ( under time pressure of course! ) and it turned out to be wrong!
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 [#permalink] New post 24 Jun 2007, 21:37
bummer, so is the correct answer B?
Thats seems to be the only logical answer
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 [#permalink] New post 25 Jun 2007, 00:20
Another explanation....

x^4+y^4=100
Max value for X is when y = 0.
So x^4 must be 100
Ans choice
a) 0...3
Now it canot be 3 since 3*3*3*3 = 81 which is less than 100
b) 3...6
Now 6*6*6*6 >100
So x has to be btw 3 and 6.

Choice 'B' is correct
Hope this helps
  [#permalink] 25 Jun 2007, 00:20
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