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Q11: If a code word is defined to be a sequence of different

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Senior Manager
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Q11: If a code word is defined to be a sequence of different [#permalink]

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New post 02 Jul 2007, 12:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Q11:
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1
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New post 02 Jul 2007, 12:11
Permutation. E.

10A5/10A4=6/1 In other words:

=[10!/(10-5)!]/[10!/(10-4)!]=6/1 thus 6:1
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New post 02 Jul 2007, 19:17
# of ways to arrange 5 items from 10 = 10P5
# of ways to arrange 4 items from 10 = 10P4

Ratio = 10P5/10P4 = 6/1
  [#permalink] 02 Jul 2007, 19:17
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Q11: If a code word is defined to be a sequence of different

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