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Given - A hall has space for t tables of equal length running along its center. Regulation requires a gap between any two tables of 1/3 length of each table. The also require an identical gap between a table and the wall at the end of the room. If the length of the hall is 296 feet and the length, in feet, of each table is an integer,
To find - how many tables can the hall accommodate ?
­
assume the length of table as 3x
wall start|-(x)-<Table3x>-<x>-<Table3x>-<x>-<Table3x>-<x>-<Table3x>-<x>-<Table3x>-<x>-...........-<x>-<Table3x>-<x>-|wall end = Length of the wall = 296 feet
for n tables
5x+(n-1)4x = 296
but 296 is = 8*37
means
5x+(n-1)4x = 8*37
But as we know
the length, in feet, of each table is an integer
from given option
only n=9
will give us
5x + 32x = 37*8
which makes 37x = 37*8
x=8 this satisfies the integer condition.
So answer is C.
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L=table length
t=no. of tables

Let us start with an edge of the wall, L/3 + L => gap and 1 table. We have t such tables => 4(L*t)/3; now at the end we add one more L/3 i.e. gap for the opposite edge of wall

From above we have,

4(L*t)/3 + L/3 = 296
L=296*3/(4t+1)
L is an integer, we have 37*3*4 in numerator.

Now from the answer choices when t=9, our denominator becomes 37 and cancels out.
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A hall has space for t tables of equal length running along its center. Regulation requires a gap between any two tables of 1/3 length of each table. The also require an identical gap between a table and the wall at the end of the room. If the length of the hall is 296 feet and the length, in feet, of each table is an integer, how many tables can the hall accommodate ?

Does that not mean 1/3rd length of table 1 + 1/3rd length of table 2 ? Doesnt that what mean "each table" means ?
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Rather than taking x as table length i took it as 3x for simplicity and created a basic skeletal structure for 3 tables.
[x][3x][x][3x][x][3x][x] where 3x are tables and x is the gap between them and the wall.

Thus we can see the total length of only table for "3" tables is "3*3x" and the length between is "4x" (no of tables + 1).

Start plugging values. When you plug number as 9. The table length will be 27x and remaining gap length will be 10x. 296 is perfectly divisible by 37.Rest all combinations arent.
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