sherlocked221B
In a apartment there are 5 floors each with 4 water taps on each floor. Any 2 taps in the same floor are connected with 4 pipes and any 2 taps in different floors are connected with 4 pipes. In one of the floors all the pipes connecting the taps with the taps in the other floors burst and in another floor all the pipes connecting the taps in that floor amongst themselves burst, though all other pipes remain intact. What is the percentage reduction in the number of pipes?
(A) 28
(B) 32
(C) 33
(D) 35
(E) 36
[Might not be a GMAT Level Question, but I came across a similar one in one of the resources I was following]
[Ambiguous and Difficult]
Here's how I got the solution.
Same floor - total pipes between 4 taps = 24
Total same floor pipes across 5 floors = 24×5 = 120
Now, for seperate floors.
Each tap is connected to any other tap on any floor via 4 pipes.
So, any tap on floor one is connected to 16 other taps via 4 pipes , hence pipe count for floor
1 =16*4*4
Each tap on Floor 2 is connected to 12 other taps - 12*4*4 ( it's connection with first floor taps have already been counted)
Total pipes ( seperate floors) = 16*4*4+12*4*4+8*4*4+16*4 = 640
Total pipes combined = 120+640= 760
Pipes burst = 24 + 256 = 280
% reduction in pipes = 280/760*100 ---> 7/19*100 (rounding off the 19 to 20) -----> 700/20 = 35%