First plot the line. The y intercept is (0,-3) the x intercept is (4,0)
The height of the triangle formed by the triangle with vertices (0,0),(0,-3),(4,0) is say h. It's area is 1/2*3*4=6. the hyp of the triangle is 5 (triplet 3:4:5).
Therefore 1/2*h*5=6 hence h =12/5=2.4
Now the min distaff between the circle and line is 2.4-radius. Radius is 1. Hence min distance is 1.4. A is the answer
What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y=(3/4)x -3 ?Posted from my mobile device
b:sqrt of 2
d:sqrt of 3