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I have been collecting Math tips & notes since I thought of GMAT & MBA. Here I am sharing them so that it can be useful to the people who are taking GMAT. These are all taken from forums and other online resources and compilation is still in progress. Will add notes & useful tips wherever I find them useful.
Updated till March 28, 2010.
Updated till March 28, 2010.
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GMAT Quant Notes_28-03-2010.pdf [286.5 KiB]
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muthumanigandan
Hmmm! I didn't collect it yet. I have strategy mentioned by one of the members here into the DS Strategies file.
I am sharing it here but then I'll post it in new topic when it's completed. Now sharing only because of you as your G-Day is near
Good Luck!
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Ok guys! I couldn't find how to take square of any number especially 2 digit numbers and I think instead of cramming squares of numbers up to 25 why not find a fast and easy way to get the square (power 2) of any number. By the way I'll update this in GMAT Quant Notes file posted in first post. And yea I'll prove this method as well
Let's start from easy one, (P.S. The beauty of math is that you can solve it in several ways)
The formula is as follows
(a-d)^2= a^2 + d^2 -2ad
which can also be written as
(a-d)^2=a^2 - 2ad + d^2
Now by taking "a" as common in underlined portion of the equation, we get
=>a*(a-2d) + d^2
Now remember this one and let's take Square of 7 (start from easy one). To take square of & we'll use above formula and the rule is always to get to nearest number multiple of 10 meaning number with "0" as unit digit or number with the base 10 . Here in case it is "10" so to get to 10 we have to add "3" to "7", which means
7= 10-3 --> same as (a-d), so "10" (the base number) is as "a" and "3" is as "d", the difference between "7" and nearest number that is multiple of 10.
Now let's solve it
7^2= (10-3)^2= [10*{10-2*(3)}] + (3)^2={10*(10-6)} + 9 = (10*4)+ 9=40+9=49 proved
Whenever the square of any number comes in your mind like in this case "7", quickly add some number(or integer) to round it to a nearest number that is multiple of 10(the one with base 10) like in this it would be "10" so the difference is "3" now similarly subtract the difference from "7" which would be 7-3=4, Now multiple 10 (base 10 number) and 4 (after subtracting the difference from actual number) and then add the square of difference which would yield as 3^2=9. now let's look at this
To take the square of 7 let's first get the difference between base 10 number and 7, which in this case is 10-7=3=d (difference), Suppose a=7 (actual number whose square is to be taken) and d=3 (difference between actual number and base 10 number), Now let's get the formula and solve it
a^2= (a-d)*(a+d) + d^2=
by solving underlined portion to (a^2 - d^2) and the put it in above equation we get
=> (a^2 - d^2) + d^2= a^2 - d^2 + d^2
now the terms in underlined portion will cancel each other and we'll get only
=> a^2 Hence proved (see above the bold term a^2 which is equal to this term)
Now solving for 7
7^2=(7+3)*(7-3)+ 3^2=10*4 + 9=40+9=49
We can also use (a+d)^2, this is used when the number to be squared is just above Base number (multiple of 10 or 100 and so on)
And (a-d)^2 is used for the number just below the base number (multiple of 10 or 100 and so on)
Now for (a+d)^= a^2 + d^2 + 2ad= a^2 + 2ad + d^2= a*(a+2d) + d^2
Let's take 11
11^2= (10+1)^2 = 10 (10 + 2*1) + 1^2= 10 (10+2) +1= 10*(12) + 1= 120 +1=121 proved
Another way to solve it is (2nd method mentioned above already)
11^2= (11-1)*(11+1) + 1^2= (10*12) + 1= 120 +1=121
it's fast and easy once you get a grasp over it, multiplying any number with a number with base 10 makes it easy as you have to just put "0"s on right side of the resultant number and then add the square of difference gives the square of the number.
Now let's practice with different numbers,
68^2= 70*(70- 2*2) + 2^2= 70*(70-4) + 4 = 70*66 + 4= 4620 + 4= 4624
by the way multiplying underlined portion is easy as (by breaking down the numbers)
70*66=70*(60+6)=(70*60) + (70*6)=4200 + 420 = 4200+400+20=4600+20=4620 and then add 4 gives 4624=68^2
similarly bold portion of above equation can also be solved as
70*(70-4)= (70*70) - (70*4)=4900 - 280=4900 -200-80=4700-80=4620 and then adding 4 gives 4624=68^2
Now with other way
68^2= (68+2)*(68-2) + 2^2=70*66 + 2^2=4620+4=4624
Now let's take 46
46^=(46+4)*(46-4) + 4^2=50*42 + 16=50*(40+2) + 16=2000+100 +16=2100+16=2116
also can be solved as
46^2=50*(50 - 2*4) + 4^2=50*(50-8) +16 = (2500-400) + 16=2100+16=2116
I think that's enough you can try other numbers you wish to, that's easy instead of just cramming squares of numbers till 25 (after you practice and then try to solve it in your mind, you'll find it easy).
By the way yet I didn't add it to the GMAT Quant Notes as the way I explained is obscure and complicated I think so if anyone of you could rephrase it in a better way then I'll add it to the File
.
Forgive my English and the way I explained (although I tried my best), haha
Hope it helps! despite the fact I wrote too much to explain a little thing.
Cheers
Let's start from easy one, (P.S. The beauty of math is that you can solve it in several ways)
The formula is as follows
(a-d)^2= a^2 + d^2 -2ad
which can also be written as
(a-d)^2=a^2 - 2ad + d^2
Now by taking "a" as common in underlined portion of the equation, we get
=>a*(a-2d) + d^2
Now remember this one and let's take Square of 7 (start from easy one). To take square of & we'll use above formula and the rule is always to get to nearest number multiple of 10 meaning number with "0" as unit digit or number with the base 10 . Here in case it is "10" so to get to 10 we have to add "3" to "7", which means
7= 10-3 --> same as (a-d), so "10" (the base number) is as "a" and "3" is as "d", the difference between "7" and nearest number that is multiple of 10.
Now let's solve it
7^2= (10-3)^2= [10*{10-2*(3)}] + (3)^2={10*(10-6)} + 9 = (10*4)+ 9=40+9=49 proved
Whenever the square of any number comes in your mind like in this case "7", quickly add some number(or integer) to round it to a nearest number that is multiple of 10(the one with base 10) like in this it would be "10" so the difference is "3" now similarly subtract the difference from "7" which would be 7-3=4, Now multiple 10 (base 10 number) and 4 (after subtracting the difference from actual number) and then add the square of difference which would yield as 3^2=9. now let's look at this
To take the square of 7 let's first get the difference between base 10 number and 7, which in this case is 10-7=3=d (difference), Suppose a=7 (actual number whose square is to be taken) and d=3 (difference between actual number and base 10 number), Now let's get the formula and solve it
a^2= (a-d)*(a+d) + d^2=
by solving underlined portion to (a^2 - d^2) and the put it in above equation we get
=> (a^2 - d^2) + d^2= a^2 - d^2 + d^2
now the terms in underlined portion will cancel each other and we'll get only
=> a^2 Hence proved
(see above the bold term a^2 which is equal to this term)Now solving for 7
7^2=(7+3)*(7-3)+ 3^2=10*4 + 9=40+9=49
We can also use (a+d)^2, this is used when the number to be squared is just above Base number (multiple of 10 or 100 and so on)
And (a-d)^2 is used for the number just below the base number (multiple of 10 or 100 and so on)
Now for (a+d)^= a^2 + d^2 + 2ad= a^2 + 2ad + d^2= a*(a+2d) + d^2
Let's take 11
11^2= (10+1)^2 = 10 (10 + 2*1) + 1^2= 10 (10+2) +1= 10*(12) + 1= 120 +1=121 proved
Another way to solve it is (2nd method mentioned above already)
11^2= (11-1)*(11+1) + 1^2= (10*12) + 1= 120 +1=121
it's fast and easy once you get a grasp over it, multiplying any number with a number with base 10 makes it easy as you have to just put "0"s on right side of the resultant number and then add the square of difference gives the square of the number.
Now let's practice with different numbers,
68^2= 70*(70- 2*2) + 2^2= 70*(70-4) + 4 = 70*66 + 4= 4620 + 4= 4624
by the way multiplying underlined portion is easy as (by breaking down the numbers)
70*66=70*(60+6)=(70*60) + (70*6)=4200 + 420 = 4200+400+20=4600+20=4620 and then add 4 gives 4624=68^2
similarly bold portion of above equation can also be solved as
70*(70-4)= (70*70) - (70*4)=4900 - 280=4900 -200-80=4700-80=4620 and then adding 4 gives 4624=68^2
Now with other way
68^2= (68+2)*(68-2) + 2^2=70*66 + 2^2=4620+4=4624
Now let's take 46
46^=(46+4)*(46-4) + 4^2=50*42 + 16=50*(40+2) + 16=2000+100 +16=2100+16=2116
also can be solved as
46^2=50*(50 - 2*4) + 4^2=50*(50-8) +16 = (2500-400) + 16=2100+16=2116
I think that's enough you can try other numbers you wish to, that's easy instead of just cramming squares of numbers till 25 (after you practice and then try to solve it in your mind, you'll find it easy).
By the way yet I didn't add it to the GMAT Quant Notes as the way I explained is obscure and complicated I think so if anyone of you could rephrase it in a better way then I'll add it to the File
.Forgive my English and the way I explained (although I tried my best), haha
Hope it helps! despite the fact I wrote too much to explain a little thing.
Cheers
