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M24#34 : Retired Discussions [Locked]

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if u want to do this question by elimination see x=1 and y =1 give the same answers , so both gets eliminated ..ofcourse A is the ans .. _________________

" What [i] do is not beyond anybody else's competence"- warren buffett My Gmat experience -http://gmatclub.com/forum/gmat-710-q-47-v-41-tips-for-non-natives-107086.html

i got the ANSWER by drawing the lines in a sheet and then finding out...is there any other easier way plz... i want to lessen the number of calculations i do...help required from the SMEs here _________________

Regards, Harsha

Note: Give me kudos if my approach is right , else help me understand where i am missing.. I want to bell the GMAT Cat

for x = 1 , the distance is 1 , so with y =1 so both of these are not answers and rest two line equations except y=x are far from the point (1,0). so left with option y=x.

may need to calculate the distance in other examples.

when the equation is y=1 then why is your line on the graph passing through y=2... also when we have x=2... the distance between y=x line and dst between x=2 line are same. i am confused badly. _________________

Hope to clear it this time!! GMAT 1: 540 Preparing again

when the equation is y=1 then why is your line on the graph passing through y=2... also when we have x=2... the distance between y=x line and dst between x=2 line are same. i am confused badly.

Hi,

The question asks out of all the lines in the option A to E, Which is closest to Point (1,0).

To your query:

Yes, the line should pass through Y=1. The distance between the point (1,0) and line Y=X and between Point (1,0) and line X=2 can be same so this tells you surely these 2 options are not the answers. You can eliminate these answer choices

Also Distance of Point (x1,y1) from a line ax+by+c=0 can be found using the formulae

|(ax1+by1+c)/\sqrt{a^2+b^2} | _________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Refer to the figure below. Pt(1,0) is closest to Blue line which is y=x and hence ans is A. The distance from line x=2 is more as can be seen in the graph.

Attachments

m 1.png [ 11.39 KiB | Viewed 1883 times ]

_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

when the equation is y=1 then why is your line on the graph passing through y=2... also when we have x=2... the distance between y=x line and dst between x=2 line are same. i am confused badly.

Here is how i did this Question without using the Distance formula

After drawing all the lines We can see tht there is a close call between (A) y = x (B) y = 1 (D) x = 2

Rest 2 could be eliminated just by seeing that their distance would be greater than the above 3 lines.

As for (B) y = 1 (D) x = 2

Both have Perpendicular Distance =1 from the point (1, 0) Now we can guess that since we have to find the shortest distance & no 2 options can have the minimum value & be the answer Thus y = x will be the answer