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manhatten review question

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manhatten review question [#permalink] New post 16 Sep 2010, 03:49
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85% (02:09) correct 14% (02:43) wrong based on 21 sessions
The relationship btwen quantities m and n is expressed by the equation 11m=5(n-42). If the diffrence between the two chosan values of n is 30, what is the difference in the corresponding values of m ?
a) 30/11
b)42/11
c)60/11
d)150/11
e)14

Looking for the best way to ans?
[Reveal] Spoiler: OA
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Re: manhatten review question [#permalink] New post 16 Sep 2010, 03:55
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say the sets of values are m1,n1 and m2,n2

11m1 = 5(n1-42)
11m2 = 5(n2-42)

Subtracting

11(m1-m2)=5(n1-n2)

So m1-m2 = (5*30)/11

OR if you are familiar with differential calculus, you can get from the equation straight away by differentiating that :

11 dm = 5 dn
and hence m = 150/11
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Re: manhatten review question [#permalink] New post 16 Sep 2010, 05:46
Yup. thats the simplest way.
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Re: manhatten review question [#permalink] New post 16 Sep 2010, 10:44
shrouded1 wrote:
say the sets of values are m1,n1 and m2,n2
11m1 = 5(n1-42)
11m2 = 5(n2-42)
Subtracting
11(m1-m2)=5(n1-n2)
So m1-m2 = (5*30)/11


smart
i would never have thought of using differential eq'ns either. kudos.
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Re: manhatten review question [#permalink] New post 16 Sep 2010, 14:31
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Another Simple way

11m=5(n-42)

Assume n = 42 to make one side equal to 0
then 11m=0
and m = 0

Repeat it by assuming n as 42+30 i.e 72
11m- 5(72-42)
11m=150
m=150/11

diff = 150/11 - 0 = 150/11
Re: manhatten review question   [#permalink] 16 Sep 2010, 14:31
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