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math problem [#permalink] New post 22 Jul 2010, 15:39
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I got this problem if 5^2 and 3^3 are factors of n*2^5*6^2*7^3 what is the least possible value of n

the answer choices were 25 27 45 75 125
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Re: math problem [#permalink] New post 22 Jul 2010, 15:46
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Jazzy12 wrote:
I got this problem if 5^2 and 3^3 are factors of n*2^5*6^2*7^3 what is the least possible value of n

the answer choices were 25 27 45 75 125


Ans is D 75

as per given question \frac{n* 2^5 * 6^2 * 7^3}{(5^2 * 3^3)} should have integral value

for this to be true n= 5^2 * 3 = 75

as 6^2 will cancel 3^2 from the denominator.
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Re: math problem   [#permalink] 22 Jul 2010, 15:46
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