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# Mixtures

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Senior Manager
Joined: 30 May 2005
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03 Aug 2005, 06:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

hello
just reposting from the intermediate forum to have more feedback
plz show your works and which equations did used thanks

A can contains a mixture of two liquids A & B in proportion 7:5 When 9 litres of mixture is drawn off and the can is filled with liquid B, the proportion of A & B becomes 7:9. How many litres of liquid A was contained by the can initially?

a]25
b]10
c]20
d]21
Manager
Joined: 28 Jun 2005
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03 Aug 2005, 19:52
mandy wrote:
:)hello
just reposting from the intermediate forum to have more feedback
plz show your works and which equations did used thanks

A can contains a mixture of two liquids A & B in proportion 7:5 When 9 litres of mixture is drawn off and the can is filled with liquid B, the proportion of A & B becomes 7:9. How many litres of liquid A was contained by the can initially?

a]25
b]10
c]20
d]21

9 lit of mix is drawn; so amount of A drawn = 21/4 lit B=15/4 lit

final amount : (A-21/4) (B-15/4+9)

ratio is (A-21/4)/(B+21/4)=7/9

substitue B=5/7A

solve for A
ans is 21
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17 Aug 2005, 07:00
Does anyone have alternative solutions to this?
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SVP
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17 Aug 2005, 07:16
Let x be the volumn of the container

7/12*(x-9)=7/16x
(x-9)/3=x/4
4x-36=3x
x=36

7/12*36=21

D
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keep on seeking, and you will find;
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Senior Manager
Joined: 29 Nov 2004
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Location: Chicago
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17 Aug 2005, 08:09
a/b = 7/5

[a-(21/4)]/[b-(15/4)+9] = 7/9

solving we get 21.
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Fear Mediocrity, Respect Ignorance

Manager
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17 Aug 2005, 08:27
Thanks Ranga, now I understand! Just in the process of overcoming the fear of mixture problems!
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Thanks!

[#permalink] 17 Aug 2005, 08:27
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# Mixtures

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