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s05#2

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s05#2 [#permalink] New post 10 May 2012, 02:10
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A
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E

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Question Stats:

100% (03:07) correct 0% (00:00) wrong based on 1 sessions
Is A Positive ?

1. x^2-2x+A is positive for all x
2. Ax^2 + 1 is positive for all x

Official Explanation -
============================
Statement (1) by itself is sufficient. x^2-2x+A=(x-1)^2 + (A-1) . For this expression to be always positive (A-1) has to be more than 0. A has to be more than 1.

Statement (2) by itself is insufficient. Ax^2+1 is positive for all even if A is 0.

The correct answer is A
==========================


Now how about this -

x^2 -2x + A > 0 for all x
=> (x-1)^2 + (A-1) > 0 for all x

now, lets say if x-1=root5, (x-1)^2 = 5,

A can be 3, hence, the expression becomes 5 + 2 = 7 > 0 ,
Is A positive, answer to question is YES
A can be -3, hence, the expression becomes 5 - 4 = 1 > 0 ,
Is A positive, answer to question is NO

Not sure if I miss something.
[Reveal] Spoiler: OA
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Re: s05#2 [#permalink] New post 10 May 2012, 02:15
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Expert's post
mitrahere wrote:
Is A Positive ?

1. x^2-2x+A is positive for all x
2. Ax^2 + 1 is positive for all x

Official Explanation -
============================
Statement (1) by itself is sufficient. x^2-2x+A=(x-1)^2 + (A-1) . For this expression to be always positive (A-1) has to be more than 0. A has to be more than 1.

Statement (2) by itself is insufficient. Ax^2+1 is positive for all even if A is 0.

The correct answer is A
==========================


Now how about this -

x^2 -2x + A > 0 for all x
=> (x-1)^2 + (A-1) > 0 for all x

now, lets say if x-1=root5, (x-1)^2 = 5,

A can be 3, hence, the expression becomes 5 + 2 = 7 > 0 ,
Is A positive, answer to question is YES
A can be -3, hence, the expression becomes 5 - 4 = 1 > 0 ,
Is A positive, answer to question is NO

Not sure if I miss something.


Welcome to GMAT Club. This question is discussed here: is-a-positive-x-2-2x-a-is-positive-for-all-x-ax-2-1-is-97302.html

Please refer to the solutions and ask if anything remains unclear.

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Intern
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Re: s05#2 [#permalink] New post 10 May 2012, 02:29
Thanks much Bunuel. That explains my query.
Re: s05#2   [#permalink] 10 May 2012, 02:29
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