If a committee of 3 people is to be selected from among 5 married couples so that the
committee does not include two people who are married to each other, how many such
committees are possible?
Total number of ways to select 3 out of 10=10C3=120
Combination with each couples 8C1 = 8
Total 5 couples 8*5=40
Combi with no couples = 120-40=80
Sorry, the part written in red is not clear. Please explain it. Thanks.
The red colored line represents all possible ways of selecting the third person in the committee aft a couple has been selected. So we need to select 1 person from the remaining 8.