Bunuel wrote:

\(\frac{2+2\sqrt{6}}{2}=\)

(A) \(\sqrt{6}\)

(B) \(2\sqrt{6}\)

(C) \(1+\sqrt{6}\)

(D) \(1+2\sqrt{6}\)

(E) \(2+\sqrt{6}\)

**Quote:**

modernx wrote:

Can anyone explain to me why this is incorrect?

1) multiple both sides of expression by 2

2) subtracting 2 from both sides

3) leaves you with 2squareroot6

Thanks

modernx , I think you must have assumed that RHS of equation = 1. It doesn't say that. So the best we can do is to simplify the fraction.

Your math, I think:

\(\frac{2+2\sqrt{6}}{2}=\)

\(\frac{2+2\sqrt{6}}{2} = 1\) (NO) -

Multiply by 2 to clear the fraction

\(2+2\sqrt{6} = 2\)

Subtract 2 from both

\(2\sqrt{6} = 0\) (NO)

Look at your statement #1. . . "both sides of the equation." There is not a right hand side value. . . It's easy to do when you are in a hurry or tired.

You cannot assume that the right hand side equals one. Hope that helps.

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