(2+2 * sqrt (6) )/2

Question

\frac{2+2\sqrt{6}}{2}=

(A)  \sqrt{6} 
(B)  2\sqrt{6} 
(C)  1+\sqrt{6} 
(D)  1+2\sqrt{6} 
(E)  2+\sqrt{6}

stne · Accepted Answer

Take 2 common from Numerator , then cancel the 2 from Numerator and Denominator

\frac{2+2\sqrt{6}}{2}= \frac{2(1+\sqrt{6})}{2}=1+\sqrt{6}

Answer C

Bunuel · Answer

SOLUTION

\frac{2+2\sqrt{6}}{2}=

(A)  \sqrt{6} 
(B)  2\sqrt{6} 
(C)  1+\sqrt{6} 
(D)  1+2\sqrt{6} 
(E)  2+\sqrt{6}

\frac{2+2\sqrt{6}}{2}=1+\sqrt{6} .

Answer: C.

PerfectScores · Answer

(2 + 2(root)6)/2 = (2/2) + (2(root6)/2 = 1 + root 6 which is answer option C.

bharatdivvela · Answer

\frac{2*(1+\sqrt{6})}{2}=1+\sqrt{6}

beatthegmat05 · Answer

Since 2 is a common factor in numerator and denominator , so taking 2 from each component of numerator and cancelling it with denominator.
(2+2*6^1/2)/2
= /2
=(2/2)(1+6^1/2)
=1+6^1/2

So the answer is (C)

nutshell · Answer

Taking the common number 2 from numerator gives us the result 1+\sqrt{6}; {2 gets canceled out}

Ans is (C)

modernx · Answer

Can anyone explain to me why this is incorrect?

1) multiple both sides of expression by 2
2) subtracting 2 from both sides
3) leaves you with 2squareroot6

Thanks

generis · Answer

modernx , I think you must have assumed that RHS of equation = 1. It doesn't say that. So the best we can do is to simplify the fraction. Your math, I think: \frac{2+2\sqrt{6}}{2}= \frac{2+2\sqrt{6}}{2} = 1 (NO) - Multiply by 2 to clear the fraction 2+2\sqrt{6} = 2 Subtract 2 from both 2\sqrt{6} = 0 (NO) Look at your statement #1. . . "both sides of the equation." There is not a right hand side value. . . It's easy to do when you are in a hurry or tired. You cannot assume that the right hand side equals one. Hope that helps.

modernx · Answer

, I think you must have assumed that RHS of equation = 1. It doesn't say that. So the best we can do is to simplify the fraction. Your math, I think: \frac{2+2\sqrt{6}}{2}= \frac{2+2\sqrt{6}}{2} = 1 (NO) - Multiply by 2 to clear the fraction 2+2\sqrt{6} = 2 Subtract 2 from both 2\sqrt{6} = 0 (NO) Look at your statement #1. . . "both sides of the equation." There is not a right hand side value. . . It's easy to do when you are in a hurry or tired. You cannot assume that the right hand side equals one. Hope that helps.

Thanks for the clear explanation

ScottTargetTestPrep · Answer

Distributing the 2 in the denominator, we have:

2/2 + (2√6)/2 = 1 + √6

Answer: C

shinichikudo · Answer

Who cannot solve this question should stay at home... lol

BrentGMATPrepNow · Answer

Here's the long solution so that students can see exactly what's happening algebraically.

\frac{2+2\sqrt{6}}{2}=\frac{2(1+\sqrt{6})}{2}

=\frac{2}{2} 	imes \frac{1+\sqrt{6}}{1}

=1 	imes \frac{1+\sqrt{6}}{1}

=1+\sqrt{6}

Answer: C

Cheers,
Brent

harshitverma14 · Answer

Let’s take √ 6 = a

Now the equation is = ( 2 + 2a )/2

Separating the terms;

2/2 + 2a/2 = 1 + a 
But a = √6

Thus option C, which is 1 + √6

Posted from my mobile device

MathRevolution · Answer

Take '2' common from the numerator and cancel '2' from the denominator.

We will get  1 + \sqrt {6}

Answer C

YolandaSami · Answer

Is this question really a 600 level question ?

YolandaSami · Answer

Is this question really a 600 level question ?

(2+2 * sqrt (6) )/2

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(2+2 * sqrt (6) )/2

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