timmaxwell8 wrote:
2. Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
A. 2 hours
B. 4 ½ hours
C. 5 ¾ hours
D. 6 hours
E. 7 ½ hours
Catches up means they will cover the same distance --> First cyclist's distance=rate*time=6*(x+3)=Second cyclist's distance=rate*time=10*x --> 6x+18=10x --> x=18/4=4 ½ hours B.
Note that we are asked: "How much time will pass before the second cyclist catches up with the first
from the time the second cyclist started biking?" So it's better x to be the second cyclist's travel time and x+3 the first one's to get the answer right away.
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85% (02:24) correct
