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Area of a right angled triangle is doubled while its base is

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Senior Manager
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Joined: 30 Aug 2003
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Area of a right angled triangle is doubled while its base is [#permalink] New post 16 Dec 2003, 10:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Area of a right angled triangle is doubled while its base is reduced to its half what % increase occours in its height?
A)300
B)370
C)400
D)150
E)510
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shubhangi

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 [#permalink] New post 16 Dec 2003, 11:07
A = 1/2 B * H

Double Area = 2A
Half base = 1/2 B

New area(NA) : NA= 2A = 1/2 * 1/2B * H
NA = A = 1/2 * 1/2 * 1/2B * H
NA = 1/4 * A

% increase = ( (NA - A)/A ) * 100% = 300%
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 [#permalink] New post 17 Dec 2003, 06:13
b = base
h = old height
H = new height

┬╜(b/2)(H) = bh .... double the original area
┬╝H = h
H = 4h

Increase in the height = NewHeight - OldHeight
= 4h - h = 3h => 300% of h
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 [#permalink] New post 17 Dec 2003, 06:25
Dammit!

I chose C because I didn't read the question right!

There's no excuse for this stuff-- If I can increase my speed, I'll have time to double check these things...
  [#permalink] 17 Dec 2003, 06:25
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Area of a right angled triangle is doubled while its base is

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