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The office of 120 is split between male and female employees at the ratio of 3:5. If 40% of the employees are married and 20 of the married employees in the office are men, how many of the women working in the office are single?

In your matrix you drew, where are you getting 45 and 75? It just seems like you are pulling them out of thin air.

I'm a bit confused on the Average 2 question on page 29.

It says that "The average of 10 consecutive integers is 12." Since this is an evenly spaced set, the median is also 12. But this is a set that contains an even number of integers, so how can the median be an integer?

E.g. the median for {2,3,4,5} is 3.5 (non-int) the median for {5,6,7,8} is 6.5 (non-int)

I'm a bit confused on the Average 2 question on page 29.

It says that "The average of 10 consecutive integers is 12." Since this is an evenly spaced set, the median is also 12. But this is a set that contains an even number of integers, so how can the median be an integer?

E.g. the median for {2,3,4,5} is 3.5 (non-int) the median for {5,6,7,8} is 6.5 (non-int)

Can someone please help?

This question? Where does the median come into play? Am i missing something?

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The office of 120 is split between male and female employees at the ratio of 3:5. If 40% of the employees are married and 20 of the married employees in the office are men, how many of the women working in the office are single?

In your matrix you drew, where are you getting 45 and 75? It just seems like you are pulling them out of thin air.

Errrr.... the ratio is 3:5, so that means if you divide 120 by (3+5), you will get 15. Now multiply 3 by 15 and 5 by 15 and you get those numbers (yes, out of thin air though with the help of some math)
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I'm a bit confused on the Average 2 question on page 29.

It says that "The average of 10 consecutive integers is 12." Since this is an evenly spaced set, the median is also 12. But this is a set that contains an even number of integers, so how can the median be an integer?

E.g. the median for {2,3,4,5} is 3.5 (non-int) the median for {5,6,7,8} is 6.5 (non-int)

Can someone please help?

This question? Where does the median come into play? Am i missing something?

The median doesn't come into play, but I just had a general question about the median of a set of numbers (that arose when I was looking through this particular Average question).

I thought the median of a set of even number of elements should be a non-int? But in this question, the mean is 12, and since it's an evenly spaced set, the median is 12 also. I just don't understand how the median can be 12?

I've got another question; these flashcards are really good btw :)

On page 33, in the Standard Deviation 3 slide, there is a question of "What is the fastest way to estimate standard deviation (without calculating it)?" I really want to know the answer, but I don't see the answer in the answer slide?

I'm a bit confused on the Average 2 question on page 29.

It says that "The average of 10 consecutive integers is 12." Since this is an evenly spaced set, the median is also 12. But this is a set that contains an even number of integers, so how can the median be an integer?

E.g. the median for {2,3,4,5} is 3.5 (non-int) the median for {5,6,7,8} is 6.5 (non-int)

Can someone please help?

This question? Where does the median come into play? Am i missing something?

The median doesn't come into play, but I just had a general question about the median of a set of numbers (that arose when I was looking through this particular Average question).

I thought the median of a set of even number of elements should be a non-int? But in this question, the mean is 12, and since it's an evenly spaced set, the median is 12 also. I just don't understand how the median can be 12?

Thanks

You are right. 12 cannot be the average of the set of 10 consecutive integers. I will change it to be 9 numbers instead. Thank you.
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I've got another question; these flashcards are really good btw :)

On page 33, in the Standard Deviation 3 slide, there is a question of "What is the fastest way to estimate standard deviation (without calculating it)?" I really want to know the answer, but I don't see the answer in the answer slide?

Am I missing something?

Many thanks. Diana

(officially, on the GMAT, you usually never have to CALCULATE the SD but you must know how to calculate it, which really means is that you will have to calculate it at least for a few numbers)

This is the answer (taking the above into consideration) We don't need to calculate as decrease in all elements of a set by a constant percentage will decrease the standard deviation of the set by the same percentage (the average is decreased by 17% as well as the difference between average (mean) and all elements or their squares. Thus the decrease in standard deviation is 17%.
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On page 44, in the Triangle 8 (Ultra Hard) question explanation,

Slide says "In the extreme case when Angle ABC is right, the triangle BOC is isosceles and thus a^2 =1/a and the area of the triangle ABC is a = 1."

I don't get how you can tell that the height of the triangle (a^2) is equal to half of the base (1/a) when the triangle is isosceles?

Thanks a lot

There is a shortcut that says if there is a triangle with angles 90, 60, and 30, then the side (hypotenuse) equals to 2x the side opposite of the 30 degree angle. Here is more about it: ds-triangle-m09q07-72173.html?kudos=1 _________________

I think there is a type on page 43 slide 10, height of equilateral tringale is given as a3/2 . I Guess height should be less than side of equilateral triangle.

I think there is a type on page 43 slide 10, height of equilateral tringale is given as a3/2 . I Guess height should be less than side of equilateral triangle.

Thank you #2 - it should be \(a\frac{\sqrt {3}}{2}\)

The square root sign got lost somewhere.... Thank you.
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