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27 Mar 2011, 22:52
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On pg.29 Algebra (Hard):
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x)
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x)
27 Mar 2011, 23:02
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annmary
On pg.29 Algebra (Hard):
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x)
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x)
Thank you
Also a more detailed explanation/discussion can be found here: m08-16-squares-75296.html
indeed!! 
