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GMAT Flashcards

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Re: GMAT Flashcards [#permalink]

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New post 23 Mar 2011, 22:32
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Here are all the PDF files for the iPhone in a single card per page. I have split them up by topic.
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Math Flashcards Geometry.pdf [579.65 KiB]
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Math Flashcards Arithmetic.pdf [674.4 KiB]
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Verbal Flashcards.pdf [661.9 KiB]
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Math Flashcards Word Problems.pdf [397.11 KiB]
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Math Flashcards Statistics.pdf [395.63 KiB]
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Math Flashcards Combinations Probability.pdf [587.07 KiB]
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Math Flashcards Algebra.pdf [312.74 KiB]
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Intro & Support Slides.pdf [274.71 KiB]
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Re: GMAT Flashcards [#permalink]

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New post 25 Mar 2011, 07:52
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yer the man. thanks dude
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New post 27 Mar 2011, 22:52
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On pg.29 Algebra (Hard):
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x) ;)
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Re: GMAT Flashcards [#permalink]

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New post 27 Mar 2011, 23:02
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annmary wrote:
On pg.29 Algebra (Hard):
answer is A option;
be cause you can write Expression in question=|x-3|+V^(2-x)+x-3
and v^(2-x) must be greater than 0 : ==>x<2
and Expression =-(x-3)+V^(2-x)+x-3=V^(2-x) ;)



Thank you
Also a more detailed explanation/discussion can be found here: m08-16-squares-75296.html
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Re: GMAT Flashcards [#permalink]

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New post 28 Mar 2011, 08:55
Thank you so much for such helpful material
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New post 06 Apr 2011, 14:34
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Thank you for this great work! You guys are amazing.
I havnt gone through all the materials, but found a minor error on P.44 of Verbal Strategies: On the answer choice bar, correct choice should be A in stead of B.
Also, on P.40, the explanation for choice C is not clear because C does not mention anything "objection".
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Re: GMAT Flashcards [#permalink]

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New post 06 Apr 2011, 16:29
Also, on p. 78 Verbal Flashcard, could you please double-check the rules for "A number of" and "The number of"?
According to the MGMAT 8, "A number of + plural noun" takes PLURAL verb, while "The number of + plural noun" takes SINGULAR verb.

On p. 85 Verbal part, the correct answer should be: Many of the students WERE surprised to learn that their exams WERE unfairly graded.
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Re: GMAT Flashcards [#permalink]

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New post 09 Apr 2011, 05:16
We are close to include GMAT Club's flashcards to iPhone/iPad apps (GMAT ToolKit and GMAT Club). So, soon you will have an easy and convenient way to work with the flashcards.
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Re: GMAT Flashcards [#permalink]

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New post 10 Apr 2011, 16:54
Sorry, please follow the rules for "a number" vs "the number" from MGMAT. I was sleep deprived when I finished that I guess? :)
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New post 18 Apr 2011, 00:41
great work indeed. Its really helpful for a quick recall while away from books.

Thanks a lot.
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New post 20 Apr 2011, 11:15
Am I missing something? Shouldn't the answer be -42??


Consecutive Numbers | Answers

Sum of consecutive integers
consecutive integers ‐8,‐9,‐7,‐6,‐5,‐4,‐3,‐2,‐1,0,1,2

The answer in the flashcards is -36.
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New post 25 Apr 2011, 23:31
This product has been updated.

Thanks to Hussain for the suggestions and improvements!
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New post 01 May 2011, 11:01
is it possible to print to pdf as one flashcard per page, so it could be used on a Kindle? thanks
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ndennis wrote:
Am I missing something? Shouldn't the answer be -42??


Consecutive Numbers | Answers

Sum of consecutive integers
consecutive integers ‐8,‐9,‐7,‐6,‐5,‐4,‐3,‐2,‐1,0,1,2

The answer in the flashcards is -36.


8-) indeed!!

(-9 + 2)/2 = -3.5
-3.5 * 12 = -42
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New post 01 May 2011, 15:43
bleemgame wrote:
ndennis wrote:
Am I missing something? Shouldn't the answer be -42??


Consecutive Numbers | Answers

Sum of consecutive integers
consecutive integers ‐8,‐9,‐7,‐6,‐5,‐4,‐3,‐2,‐1,0,1,2

The answer in the flashcards is -36.


8-) indeed!!

(-9 + 2)/2 = -3.5
-3.5 * 12 = -42



Thank you. Just so you don't think that I am a lame dude who can't count (add in this case), I managed to write the sequence wrong down (in this case, I am really a guy who can't type), and typed up -8, -9, -7, etc, thus starting it at -8. I have fixed that part but did not check the solution. That has been fixed this time.

Thank you.
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Re: GMAT Flashcards [#permalink]

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New post 01 May 2011, 15:46
alexgmd wrote:
is it possible to print to pdf as one flashcard per page, so it could be used on a Kindle? thanks



You mean like this?
gmat-flashcards-108651-60.html#p898551
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Re: GMAT Flashcards [#permalink]

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New post 01 May 2011, 15:52
oh, i missed it :)) thanks!!! i went through pages 1-3, but didn't check page 4 for an answer - shame on me :-D

bb wrote:
alexgmd wrote:
is it possible to print to pdf as one flashcard per page, so it could be used on a Kindle? thanks



You mean like this?
gmat-flashcards-108651-60.html#p898551
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New post 02 May 2011, 12:57
still working my way through these cards - very useful (thanks!!) :)

On page 38, I tried the following - is this a correct method for a quick solution? (or am I just lucky to get the right number out of it?)

Using only one piece of information that 20 chickens eat 3 days worth of food..... (and assuming all chickens eat the same amount)

1 day is 1/3 of 3 days... 1 chicken will eat 1/20 of the amount in 3 days, so will eat 1/3 of 1/20 in one day.....

1 chicken = (1/3)(1/20) = 1/60.

Therefore 60 chickens needed to eat a day's worth of food.
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Re: GMAT Flashcards [#permalink]

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New post 02 May 2011, 14:41
Still loving the slides :) (sorry - another question)

Page 47 - Coordinate Geometry 3.

As the axes do not have scales, you can't really say whether the gradient of A is greater or less than 1... if x and y are set to the same scale it actually looks jolly close to 1... (depends on how the resolution is set on your monitor!!!) to allow the student to be sure whether the slope is less than / greater than 1, and to answer correctly, some numbers could help :)
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Re: GMAT Flashcards [#permalink]

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New post 02 May 2011, 15:08
P48, Coordinate Geometry 6

"Find the equation of a line passing through the points A (5,4) and B (2,3)"

using Y = MX + C (was always taught to use c and not b... sue me :) )

As change in y is 1, and change in x is 3, that gives a line of gradient 1/3.

Putting this into the equation and solving where x = 5 and y = 4...

4 = 5/3 + c ... therefore c = 7/3

testing in B where x = 2 and y = 3
3 = 2/3 + 7/3 (correct)

Solution therefore y = x/3 + 7/3 :)

<< since posting I noticed that the solution offered actually uses 6,3 as point B and not 2,3 as in the question ;)
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Re: GMAT Flashcards   [#permalink] 02 May 2011, 15:08

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