Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

This is very tricky. E. Just guessing. well it cant be B since you need to define what is line r and what is line s. And information IMO is not sufficient.

line r: y=ax+b line s: g=bx+c is b<c? statement 1: intersection of r and s is negative or y<0 and ax+b=cx+d <=> (a-c)x=d-b x=(d-b)/(a-c) <0 we cant conclusion about this so insufficient statement2: the slope of r < the slop of s or a<c , we dont know about b and d thus insufficient, 1+2. (d-b)/(a-c)<0 so or d-b< o and a-C> o or (d-b)>o or (a-c)< o from statement 2 we know that a<c thus eliminate the condision that (d-b)<0 and (a-c)>0 so sufficient C

I am not sure if they are considering the +/- or the modulus of intercept. In case it is magnitude (modulus) of the intercept the answer is E. But consider the sign of the intercept, the answer is C.

line r: y=ax+b line s: g=bx+c is b<c? statement 1: intersection of r and s is negative or y<0 and ax+b=cx+d <=> (a-c)x=d-b x=(d-b)/(a-c) <0 we cant conclusion about this so insufficient statement2: the slope of r < the slop of s or a<c , we dont know about b and d thus insufficient, 1+2. (d-b)/(a-c)<0 so or d-b< o and a-C> o or (d-b)>o or (a-c)< o from statement 2 we know that a<c thus eliminate the condision that (d-b)<0 and (a-c)>0 so sufficient C

line r: y=ax+b line s: g=bx+c

I think

line r: y=ax1+b line s: g=bx2+c if line r: y=ax+b line s: g=bx+c

it means that 2 lines intersect together at a common point?

Shuwa - I think diebeatsthegmat has a typo in his solution when he defines the lines the first time line r: y=ax+b, line s: g=bx+c .

In reality, he has defined the line s as y= cx+d as can be seen in his calculation for statement 1.

Also, defining lines as y=ax+b and y= cx+d, does not imply that they intersect at the same point, it is just a general form of equation for any line that has a defined slope (a and c for two lines here) and a defined y intercept (b and d for lines here).

I am not sure if they are considering the +/- or the modulus of intercept. In case it is magnitude (modulus) of the intercept the answer is E. But consider the sign of the intercept, the answer is C.

Hope the helps!

The question simply asks if y intercept of r is less than y intercept of s, so we need to take the value of the intercept and not the absolute value.

A general line would be y=mx+c where y intercept is c which can be negative or positive or zero, so we need to just compare the actual value and that would involve incorporating the sign of the intercept as well.

I think diebeatsthegmat has the best approach to solve this without any confusion whatsoever.

Thanks beyondgmatscore. Yeah all ordered now. So I change this statement. Answer is C - whether you use visual approach or algebra.

beyondgmatscore wrote:

gmat1220 wrote:

I came up with 2 cases.

Case 1 intercept(r) > intercept(s) Case II intercept(r) > intercept(s)

I am not sure if they are considering the +/- or the modulus of intercept. In case it is magnitude (modulus) of the intercept the answer is E. But consider the sign of the intercept, the answer is C.

Hope the helps!

The question simply asks if y intercept of r is less than y intercept of s, so we need to take the value of the intercept and not the absolute value.

A general line would be y=mx+c where y intercept is c which can be negative or positive or zero, so we need to just compare the actual value and that would involve incorporating the sign of the intercept as well.

I think diebeatsthegmat has the best approach to solve this without any confusion whatsoever.

I'm pretty sure I marked C without doing math on this, just drawing a few sketches knowing that:

I) the slopes can be anything, the intercepts can be anything, just that their points together are in Quadrant III (-x,-y); not sufficient

II) slope R is greater than slope S, just the steepness of the line, you can put the lines anywhere in the plane or any quadrant; not sufficient

Together, intercepting in Quadrant III and bigger slope? visually it just seems that it would have to hit higher all the time on the Intercept? am i wrong to think of it this way? _________________

I am not sure if they are considering the +/- or the modulus of intercept. In case it is magnitude (modulus) of the intercept the answer is E. But consider the sign of the intercept, the answer is C.

Hope the helps!

The question simply asks if y intercept of r is less than y intercept of s, so we need to take the value of the intercept and not the absolute value.

A general line would be y=mx+c where y intercept is c which can be negative or positive or zero, so we need to just compare the actual value and that would involve incorporating the sign of the intercept as well.

I think diebeatsthegmat has the best approach to solve this without any confusion whatsoever.

yep, thats also correct in some cases, anyways i am a girl! i am a her, not a him lol

gmatclubot

Re: xy-plane- Slope
[#permalink]
05 Mar 2011, 07:59

Part 2 of the GMAT: How I tackled the GMAT and improved a disappointing score Apologies for the month gap. I went on vacation and had to finish up a...

I’m a little delirious because I’m a little sleep deprived. But whatever. I have to write this post because... I’M IN! Funnily enough, I actually missed the acceptance phone...

So the last couple of weeks have seen a flurry of discussion in our MBA class Whatsapp group around Brexit, the referendum and currency exchange. Most of us believed...

This highly influential bestseller was first published over 25 years ago. I had wanted to read this book for a long time and I finally got around to it...