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OE is S1 is true even if G =1/10 and K=1/10 ; therefore, it is not sufficient. S2 is obviously insufficient, but together they are sufficient, because then G> K^2 > 1 and this implies G> K

My answer is A

When 1. G = 2, K =1 G >K^2 is TRUE, Is G<K - No/False - Suff 2. G = 1/2, K =1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 3. G = 1/2, K =-1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 4. G = 9, K = -2 G >K^2 is TRUE, Is G<K - No/False - Suff 5. G = 1/3, K = -1/3 G >K^2 is TRUE, Is G<K - No/False - Suff 6. G = 1/3, K = 0 G >K^2 is TRUE, Is G<K - No/False - Suff

I could not think of an example which will the contradict the answer

Am I missing something here I am completely confused

Livestronger, you were close enough on your number substitution sample #2. But why did you chose the same numbers for both G and K.

If you had chosen G = 1/3 and K = 1/2. It satisfies, G > K^2. And clearly answers if G < K. it appears sufficient. But let's try with another substitution. G = 1 and K = 1/2. Again G > K^2 is satisfied. But this time G < K gives you a different answer. Now that's the crucial part(IMHO) of DS. If you can come up with 2 different results for the original question stem, then that particular choice is not Sufficient. Safely POE on that..so A and D are gone.

statement #2, seems obvious. It is definitely not sufficient to answer whether G < K. All we know if G > 0 and K > 0 and that they are integers. So B is gone.

Now together, they tell a story. Statement 2 affirms us that G and K are not fractions. So our only other contradiction about statement 1 is eliminated. Which leaves us with the fact that if G > 0 and K > 0 and both are integers, then if G > K^2, then always G is > K.

HTH... _________________

excellence is the gradual result of always striving to do better

From statement 1: 1. If G = 0.5 and K = 0.7, G > K^2. here G < K. 2. If G = 5 and K = 2, G > K^2. Here G > K.

NSF.

From statement 2:

Either one is greater or smaller than the other. NSF.

From Statement 1 and 2:

G > K or G is not smaller than K. So Suff....

//C//

LiveStronger wrote:

Is G< K ? 1. G>K^2 2. G and K are positive integers

OA is C OE is S1 is true even if G =1/10 and K=1/10 ; therefore, it is not sufficient. S2 is obviously insufficient, but together they are sufficient, because then G> K^2 > 1 and this implies G> K

My answer is A

When 1. G = 2, K =1 G >K^2 is TRUE, Is G<K - No/False - Suff 2. G = 1/2, K =1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 3. G = 1/2, K =-1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 4. G = 9, K = -2 G >K^2 is TRUE, Is G<K - No/False - Suff 5. G = 1/3, K = -1/3 G >K^2 is TRUE, Is G<K - No/False - Suff 6. G = 1/3, K = 0 G >K^2 is TRUE, Is G<K - No/False - Suff

I could not think of an example which will the contradict the answer

Am I missing something here I am completely confused

Livestronger, you were close enough on your number substitution sample #2. But why did you chose the same numbers for both G and K.

If you had chosen G = 1/3 and K = 1/2. It satisfies, G > K^2. And clearly answers if G < K. it appears sufficient. But let's try with another substitution. G = 1 and K = 1/2. Again G > K^2 is satisfied. But this time G < K gives you a different answer. Now that's the crucial part(IMHO) of DS. If you can come up with 2 different results for the original question stem, then that particular choice is not Sufficient. Safely POE on that..so A and D are gone.

statement #2, seems obvious. It is definitely not sufficient to answer whether G < K. All we know if G > 0 and K > 0 and that they are integers. So B is gone.

Now together, they tell a story. Statement 2 affirms us that G and K are not fractions. So our only other contradiction about statement 1 is eliminated. Which leaves us with the fact that if G > 0 and K > 0 and both are integers, then if G > K^2, then always G is > K.

HTH...

Ahhh, I just simply couldn't think of that example Thanks masuhari and GMAT TIGER

Is G < K ? (1) G > K^2 (2) G and K are positive integers.

Statement 2: G and K are positive integers. G = 1 and K = 2 => G < K is True. G = 2 and K = 1 => G < K is False. Statement 2 is Clearly not sufficient by itself.

This eliminates answers B and D.

Remember this statement says G and K are positive and G and K are integers. So, G and K are not fractions.

Statement 1: G > K^2 G = 5 and K = 2: 5 > 4, so G > K^2 is True, but G < K is False. G = 1/3 and K = 1/2: 1/3 > 1/4, so G > K^2 is True, but G < K is True. Statement 2 is Clearly not sufficient by itself.

This eliminates the answer A.

Take Both Statement 1 and 2: G > K^2 and G and K are positive integers. In this case, G and K are position and are integers, so cannot be fractions.

Examples: G = 2 and K = 1: 2 > 1, so G > K^2 is True, but G < K is False. G = 5 and K = 2: 5 > 4, so G > K^2 is True, but G < K is False. G = 101 and K = 10: 101 > 100, so G > K^2 is True, but G < K is False.

So, the result is consistent and both statement 1 and 2 jointly are sufficient to answer is G < K.

The answer choice is C.

Do not forget to award me with Kudos+1, if this helps you!! Cheers!!!

The text in red contains an error. If you use information from both statements, you should take such G that follows S1 (\(G>K^2\)). The text in red clearly contradicts S1, so this is not a valid proof. S1+S2 is sufficient, OA is C.

I hope it helps you.

lnarayanan wrote:

We know that -

is G<K

Opt - A) G>K^2 - alone not sufficient

Opt - B) G and K are +ve integers - alone not sufficient

Combaining together, (two possibilities ) ex) G=3 , K = 10 implies 3>100 = False G=20 , K = 3 implies 20>9 = True. So two answers are contradicting each other.

it took me so much time, and so many examples to get this one right! Lesson learnt: use fractions when it is NOT given that the numbers are "integers". _________________

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If you feel like you're under control, you're just not going fast enough. A goal without a plan is just a wish. You can go higher, you can go deeper, there are no boundaries above or beneath you.

1) G > K to power 2 2) G and K are positive integers.

Lets take (1)

Both G and K can be positive or negative integers or even fractions. (a)If both are positive, when G >K^2, => G > K (b)If both are negative, when G cannot be greater than K^2 which will then become positive (c)When both are fractions, we can get all kinds of results.

So, (1) is not enough for us to get an answer - Choce (A) and (D) are ruled out.

Now lets take (2) Both G and K are postive integers, so G < K only when exact values of G and K are known, which we dont know so (2) is not enough and option (B) is ruled out.

Now its either (C) or (E).

Lets evaluate C -

If both are positive integers and G>K^2, as explained in (a) above, this means that G > K always. Hence (C) is the choice.

Um, you guys, where can I find the answer options? I'm new and feel really stupid as obviously everyone else can find them but me...

Thanks!

This is a data sufficiency question. Options for DS questions are always the same.

The data sufficiency problem consists of a question and two statements, labeled (1) and (2), in which certain data are given. You have to decide whether the data given in the statements are sufficient for answering the question. Using the data given in the statements, plus your knowledge of mathematics and everyday facts (such as the number of days in July or the meaning of the word counterclockwise), you must indicate whether—

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked. C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked. D. EACH statement ALONE is sufficient to answer the question asked. E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

OE is S1 is true even if G =1/10 and K=1/10 ; therefore, it is not sufficient. S2 is obviously insufficient, but together they are sufficient, because then G> K^2 > 1 and this implies G> K

My answer is A

When 1. G = 2, K =1 G >K^2 is TRUE, Is G<K - No/False - Suff 2. G = 1/2, K =1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 3. G = 1/2, K =-1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 4. G = 9, K = -2 G >K^2 is TRUE, Is G<K - No/False - Suff 5. G = 1/3, K = -1/3 G >K^2 is TRUE, Is G<K - No/False - Suff 6. G = 1/3, K = 0 G >K^2 is TRUE, Is G<K - No/False - Suff

I could not think of an example which will the contradict the answer

Am I missing something here I am completely confused

m03 q14

Is \(x < y\) ?

(1) \(x>y^2\) --> if \(x=2\) and \(y=1\) then the answer is NO but if \(x=\frac{1}{3}\) and \(y=\frac{1}{2}\) then the answer is YES. Not sufficient.

(2) \(x\) and \(y\) are positive integers. Not sufficient on its own.

(1)+(2) Since from (2) \(x\) and \(y\) are positive integers then from (1) \(x>y^2\geq{1}\), which means that \(x>y\), so the answer to the question is NO. Sufficient.