Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

N = P + Q + R and P, Q, R is the consecutive integers. N = X [#permalink]
11 Nov 2005, 08:16

1

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

100% (04:20) correct
0% (00:00) wrong based on 2 sessions

N = P + Q + R and P, Q, R is the consecutive integers.
N = X * Y * Z and X, Y, Z is the consecutive integers, too.
What is the remainder of N to be divided by 5 ?

(1) The remainder of P to be divided by 5 is 1
(2) The remainder of X to be divided by 5 is 1 _________________

N = P + Q + R and P, Q, R is the consecutive integers. N = X * Y * Z and X, Y, Z is the consecutive integers, too. What is the remainder of N to be divided by 5 ?

(1) The remainder of P to be divided by 5 is 1 (2) The remainder of X to be divided by 5 is 1

It's E.
Consider two cases:
case 1: N= 1+2+3 = 1*2*3=6
in this case, P=X=1 which divided by 5 has remainder of 1. (exactly what's from the two statements)
N=6 ---> the remainder of N to be divided by 5 is 1.

case 2: N= 1+0+-1 = 1*0* (-1) = 0
in this case, P=X= 1which divided by 5 has remainder of 1 ( exactly the two statements)
N= 0 ---> the remainder of N to be divided by 5 is 0.

=> we can't find exactly what the remainder is even if we combine two statements.

i would go with D.
N = P + Q + R and P, Q, R is the consecutive integers.
N = X * Y * Z and X, Y, Z is the consecutive integers, too.
What is the remainder of N to be divided by 5 ?

(1) The remainder of P to be divided by 5 is 1
take any value of P where remainder is 1 6,16,11,21...
and multiply the each next to consicutive integer like
6+7+8/5=Remainder 1
16+17+18/5=Remainder 1
21+22+23/5=Remainder 1

how do you know P is the smallest consecutive number?
for all I know P could 6, Q=5 and R =4

?? did you read my post??

cool_jonny009 wrote:

i would go with D. N = P + Q + R and P, Q, R is the consecutive integers. N = X * Y * Z and X, Y, Z is the consecutive integers, too. What is the remainder of N to be divided by 5 ?

(1) The remainder of P to be divided by 5 is 1 take any value of P where remainder is 1 6,16,11,21... and multiply the each next to consicutive integer like 6+7+8/5=Remainder 1 16+17+18/5=Remainder 1 21+22+23/5=Remainder 1

I also got D assuming that the number are in order. In questions when they say consecutive, I think, I have always come across ordered sequence (ascending)

P = 1, Q = 2, R = 3 -> N = (1+2+3)/5 -> Remainder is 1
P = 6 Q = 5, R = 7 -> N = (6+5+7)/5 -> Remainder is 3

(2) Insufficient

Let X = b]1[/b], 6, 11, 16 ......

X = 1, Y = 2, Z = 3 -> N = (1*2*3)/5 -> Remainder is 1
X = 1, Y = 0, Z = -1 -> N = (1*0*-1)/5 -> Remainder is 0

I believe this question is testing whether it is correct to assume P, Q and R and X, Y and Z are in order. I don't think this is valid assumption. If the assumption was valid, then this would be an easy question.

we don't know the order, first of all, secondly even if we know the order, we don't the whether the consequtive integers are positive or negative. _________________

Throw my vote with D too. When it says x,y,z are consecutive integers I always think I can assume x=n-1, y=n and z=n+1. In other words, I'm assuming their orders. It's a good point to notice though. It would be nice for us to see if it is a official question and if the anwer does not confirm our assumption. _________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

The basic requirement for remainder of a number X when divide by n is:

X = n.q + r ........ (where q is an integer quotient and r the remainder)

So, if X is negative:

-X = -n.q - r

eg. -6/5

-6 = -1(5) - 1

X = n.q + r

here the property of r is:

0<= r <q

in this example, -1 < 0

I guess, we should leave as out-of-scope as I did not find any problem where we need to think about this. ETS only talks about remainer in the context of positive integers.
The only think to remember is:
q <> 0 _________________

Whether you think you can or think you can't. You're right! - Henry Ford (1863 - 1947)

Hello everyone! Researching, networking, and understanding the “feel” for a school are all part of the essential journey to a top MBA. Wouldn’t it be great... ...

Are you interested in applying to business school? If you are seeking advice about the admissions process, such as how to select your targeted schools, then send your questions...