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Re: For positive integers x and y, which of the following can [#permalink]
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Bunuel wrote:
emmak wrote:
For positive integers x and y, which of the following can be written as y^2?

A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!


Plug values: if x=5, then x^2-9=16=4^2.

Answer: C.


How the solution can be made easy? I was plugging in smaller numbers than 5 and in such cases even (C) fails. As the time was running out, I made an educated guess as (C) and it turned out to be right !!!!
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Re: For positive integers x and y, which of the following can [#permalink]
Bunuel wrote:
emmak wrote:
For positive integers x and y, which of the following can be written as y^2?

A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!


Plug values: if x=5, then x^2-9=16=4^2.

Answer: C.


Although I understood the explanation, but it would fail if I put x=4. In other words, why did you select x=5?
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Re: For positive integers x and y, which of the following can [#permalink]
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The question is asking "Which of these equations could equal a perfect square?"

If you're familiar with number properties regarding perfect squares, you should be able to rule out everything except the correct answer.

the fact that 5^2 - 4^2 is equal to 3^2 should be a pattern that you have memorized (esp. with regards to right triangles)
also, another one you might see often is some form of 13^2-5^2=12^2
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Re: For positive integers x and y, which of the following can [#permalink]
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but if we assume in option c, X=10 than it is= 100-9=91 (which is not a square root). how option c is valid?


Bunuel wrote:
emmak wrote:
For positive integers x and y, which of the following can be written as y^2?

A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!


Plug values: if x=5, then x^2-9=16=4^2.

Answer: C.
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Re: For positive integers x and y, which of the following can [#permalink]
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poojamittal63 wrote:
but if we assume in option c, X=10 than it is= 100-9=91 (which is not a square root). how option c is valid?


Bunuel wrote:
emmak wrote:
For positive integers x and y, which of the following can be written as y^2?

A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!


Plug values: if x=5, then x^2-9=16=4^2.

Answer: C.


The question asks "which of the following CAN be written as y^2". If x=5, then x^2−9 CAN be written as 4^2.
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For positive integers x and y, which of the following can [#permalink]
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For positive integers x and y, which of the following can be written as y^2?
A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!

It is worth while to remember that the only factorial that are perfect square is 0 and 1. {0!=1 and 1!=1 and \(1=1^2}\)
If you know this fact then you can figure out that the answer is C
But just to reconfirm I will solve this question.
Now lets attack the problem.

A. (x+1)! = OHHHH ! so close, If x= 0 then this could have been our answer, \({0+1=1^2}\)but question stem tells us that x and y are +ve integer. 0 is not a positive integer.

B. (x+9)! = Cannot be a perfect square. No factorial except 1 is a perfect square

C. x^2−9 = Yes ! this can be ; take \(x= 3; 3^2-9 = 0-0 = 0 ; y= 0^2\) ||||| take \(x=5; 5^2-9=16 ; Y^2=4^2\)

D. x^2+1 = NO ! if you add 1 to a perfect square you cannot another perfect square; exception is 0 ; \(0^2+1 = 1 = 1^2\)

E. ((x+1)^2)!= Again so close if x= 0 then we could have a perfect square but x cannot be zero; so this expression cannot be a perfect square.





emmak wrote:
For positive integers x and y, which of the following can be written as y^2?

A. (x+1)!
B. (x+9)!
C. x^2−9
D. x^2+1
E. ((x+1)^2)!
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Re: For positive integers x and y, which of the following can [#permalink]
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Re: For positive integers x and y, which of the following can [#permalink]
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