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For any positive x, y and z if x is n% of y and z is m% of y

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hapless12
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For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   13 Jun 2014, 00:37
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56% (01:36) correct 44% (01:40) wrong based on 248 sessions
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For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%
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E
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Bunuel
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   13 Jun 2014, 01:18
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hapless12 wrote:
For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%


x is n% of y: \(x=\frac{n}{100}*y\);

z is m% of y: \(z=\frac{m}{100}*y\);

What percentage must x be of z: \(\frac{x}{z}*100=\frac{n}{m}*100\).

Answer: E.
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   13 Jun 2014, 01:19
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Bunuel wrote:
hapless12 wrote:
For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%


x is n% of y: \(x=\frac{n}{100}*y\);

z is m% of y: \(z=\frac{m}{100}*y\);

What percentage must x be of z: \(\frac{x}{z}*100=\frac{n}{m}*100\).

Answer: E.


Similar questions to practice: if-25-percent-of-p-is-equal-to-10-percent-of-q-and-pq-0-th-168485.html
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   16 Jun 2014, 04:43
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hapless12 wrote:
For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%



x is n% of y MEANS x= (n/100 )* y------------------------eq1

z is m% of y MEANS z= (m/100 )* y------------------------eq2

Find equation of x & z
substitute value of y from 2nd equation into Ist equation
so x= (n/100)*(100z/m)
so x= (n/m)z
or x= (100n/m)z/100
so answer is 100n/m %
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   22 May 2017, 18:44
Expert Reply
hapless12 wrote:
For any positive x, y and z if x is n% of y and z is m% of y then what percentage must x be of z?
A. (n/m)%
B. (m × n)%
C. (100 / [m × n]) %
D. (100 × m/n)%
E. (100 × n/m)%


We are given:

x = (n/100)y

x/(n/100) = y

100x/n = y

AND

z = (m/100)y

z/(m/100) = y

100z/m = y

We can equate our two equations and then express x as a percentage of z:

100x/n = 100z/m

100x/100z = not n/m

x/z = n/m

Thus, x/z * 100 = n/m * 100.

Answer: E
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   01 Jul 2018, 17:19
X=n/100 y
Z=m/100 y
X=n/100*100z/m
X=n/m z
Answer E


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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink] For any positive x, y and z if x is n% of y and z is m% of y   21 Oct 2022, 20:24
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Re: For any positive x, y and z if x is n% of y and z is m% of y [#permalink]
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