Last visit was: 06 Jun 2024, 03:54 It is currently 06 Jun 2024, 03:54
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Director
Director
Joined: 14 Sep 2005
Posts: 525
Own Kudos [?]: 1213 [0]
Given Kudos: 0
Location: South Korea
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 13 Nov 2003
Posts: 356
Own Kudos [?]: 178 [0]
Given Kudos: 0
Location: BULGARIA
Concentration: INSURANCE, RISK MANAGEMENT
 Q49  V38
Send PM
User avatar
Director
Director
Joined: 30 Sep 2004
Posts: 687
Own Kudos [?]: 1458 [0]
Given Kudos: 0
Location: Germany
Send PM
User avatar
Director
Director
Joined: 14 Sep 2005
Posts: 525
Own Kudos [?]: 1213 [0]
Given Kudos: 0
Location: South Korea
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
Good job !

The OA is 135.
User avatar
Manager
Manager
Joined: 30 Aug 2005
Posts: 138
Own Kudos [?]: 19 [0]
Given Kudos: 0
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
How about this?
You can select two groups out of 6 in 6C2 ways. within each groups, you can select one person in 3 ways.

So, 6C2*3*3= 135
User avatar
Manager
Manager
Joined: 30 Aug 2005
Posts: 138
Own Kudos [?]: 19 [0]
Given Kudos: 0
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
Why can't this be-
Select one group out of 6 in 6C1 ways, select one person out of 3 in 3 ways

Then select another group in 5C1 ways, select one person out of 3 in 3 ways

so, combinatons = 6*3*5*3=270

What am I missing?
User avatar
Director
Director
Joined: 14 Sep 2005
Posts: 525
Own Kudos [?]: 1213 [0]
Given Kudos: 0
Location: South Korea
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
rianah100 wrote:
Why can't this be-
Select one group out of 6 in 6C1 ways, select one person out of 3 in 3 ways

Then select another group in 5C1 ways, select one person out of 3 in 3 ways

so, combinatons = 6*3*5*3=270

What am I missing?


You double counted the handshakes.

Suppose there are 6 groups - A, B, C, D, E, and F.

There are 3 members in group A, and they are A1, A2, and A3.
There are 3 members in group B, and they are B1, B2, and B3.

First, you pick group A, and pick person A1.
Then you pick group B, and pick person B1.

Again,
first, you pick group B, and pick person B1.
then you pick group A, and pick person A1.

The above two cases have to be counted as one.

Therefore, you have to divide your result by 2.
User avatar
Senior Manager
Senior Manager
Joined: 09 Jul 2005
Posts: 320
Own Kudos [?]: 145 [0]
Given Kudos: 0
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
When two different groups meet each other there are 9 handshakes. Thefeore the total number of handhakes will be:

9*5 + 9*4 + 9*3 + 9*2 + 9 =135
User avatar
Manager
Manager
Joined: 15 Apr 2005
Posts: 159
Own Kudos [?]: 32 [0]
Given Kudos: 0
Location: India, Chennai
Send PM
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
Total no of people = 18
Total no of handshakes = 18C2
Total no of handshakes within the same company = 3C1, so for 6 companies it is 6*3C1= 18
18C2-18
= 17*18/2 - 18
= 18*(17/2-1)
= 9 *(15) = 135



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
GMAT Club Bot
Re: Each of the 6 companies sends 3 people to a conference. [#permalink]
Moderators:
Math Expert
93575 posts
Senior Moderator - Masters Forum
3131 posts