I get D, but I'm not sure that my method is sound.
You have A + B + C + D = total testers. Stating the variety they think is most similar to freshly squeezed orange juice means each person should get 1 vote.
x = total number of testers
A + B + C + D
.61x + (.5)(.61x) + 65 + D = x
.61x + .305x + 65 + D = x
I took total testers = 1000 because that gives me nice numbers to deal with. Also, if I use 200 total testers, that gives me A = 122, B = 61, C = 65...that's over 200 without considering D.
x = 400
A = 244, B = 122, C = 65..also over 400
x = 600
A = 366, B = 183 C = 65....also over 600
x = 800
A = 488, B = 244, C = 65...D = 3...not an option on the list.
x = 1000
A = 610 B = 305 C = 65 D = 20....the first time I get an answer that is an option in the question.
I suppose there is another way to figure this up
.61x + .305x + 65 + D = x
.915 + 65 + D = x
65 + D = 0.085x
Even if D = 0, that leaves 65 / 0.085 = x...so the minimum number of testers (with D = 0) is 764.7.
So we know the total number can't be less than that...and we've already seen 800 doesn't work...next logical step is 1000 which results in 20 and it's a possible answer.
nirimblf
A Juice manufacturer organized taste-testing sessions featuring four brands of orange joice, A B C and D. All customers who participated told the organizer which variety they thought was the most similar to freshly squeezed orange juice. Exactly 61% preferred brand A and exactly half as many preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?
A. 8
B. 11
C. 14
D. 20
E. 31