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# A juice manufacturer organized taste-testing sessions featuring four

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Intern
Joined: 29 Jun 2008
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A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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Updated on: 19 Mar 2015, 06:54
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55% (hard)

Question Stats:

70% (03:03) correct 30% (03:13) wrong based on 244 sessions

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A juice manufacturer organized taste-testing sessions featuring four brands of orange juice, A, B, C and D. All customers who participated told the organizer which variety they thought was the most similar to freshly-squeezed orange juice. 61% preferred brand A and exactly half as many preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?

(A) 1
(B) 8
(C) 14
(D) 20
(E) 27

Originally posted by nirimblf on 07 Jul 2008, 10:53.
Last edited by Bunuel on 19 Mar 2015, 06:54, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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27 Oct 2018, 20:02
1
Nikhilaery wrote:
A juice manufacturer organized taste-testing sessions featuring four brands of orange juice, A, B, C and D. Out of all customers who participated, 61% preferred brand A and exactly half as much preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?

A. 8
B. 11
C. 14
D. 20
E. 31

So the QUESTION must be meaning that each can prefer only one drink...
So A and B is preferred by $$61 +\frac{61}{2}=61+30.5=91.5$$%..
Remaining 8.5% prefer C and D..
If 65 prefer C, # preferring $$D = 8.5*t-65$$, where t is total
Now 8.5t will have 0 or 5 as units digit..
If 0 then D will have 5 as units digit and if 5, then 5-5=0
Here only choice D has a 0 so answer D..
Inference- total is 100, 8.5% means 85, Cis 65 so D is $$85-65=20$$

D
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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07 Jul 2008, 11:03
Hi,Think that the ans is 20.
A and B together are 91.5%. This means that C and D together are 8,5%.Since it is given that C is 65 then the total number of people is at least 800. The next input is 1000 which gives 85, 65 for C and 20 for D
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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07 Jul 2008, 11:14
2
total number of people is T
61% of T is an integer --> T is a multiple of 100
31.5% of T is an interger --> T is multiple of 200

C+D = 8.5% * T = 65 + x

After here i looked at the answer choices and found 20. it is satifying both conditions...

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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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07 Jul 2008, 11:21
I get D, but I'm not sure that my method is sound.

You have A + B + C + D = total testers. Stating the variety they think is most similar to freshly squeezed orange juice means each person should get 1 vote.

x = total number of testers

A + B + C + D
.61x + (.5)(.61x) + 65 + D = x
.61x + .305x + 65 + D = x

I took total testers = 1000 because that gives me nice numbers to deal with. Also, if I use 200 total testers, that gives me A = 122, B = 61, C = 65...that's over 200 without considering D.

x = 400
A = 244, B = 122, C = 65..also over 400

x = 600
A = 366, B = 183 C = 65....also over 600

x = 800
A = 488, B = 244, C = 65...D = 3...not an option on the list.

x = 1000
A = 610 B = 305 C = 65 D = 20....the first time I get an answer that is an option in the question.

I suppose there is another way to figure this up

.61x + .305x + 65 + D = x
.915 + 65 + D = x
65 + D = 0.085x

Even if D = 0, that leaves 65 / 0.085 = x...so the minimum number of testers (with D = 0) is 764.7.

So we know the total number can't be less than that...and we've already seen 800 doesn't work...next logical step is 1000 which results in 20 and it's a possible answer.

nirimblf wrote:
A Juice manufacturer organized taste-testing sessions featuring four brands of orange joice, A B C and D. All customers who participated told the organizer which variety they thought was the most similar to freshly squeezed orange juice. Exactly 61% preferred brand A and exactly half as many preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?

A. 8
B. 11
C. 14
D. 20
E. 31

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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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08 Jul 2008, 08:05
1
My (usual) silly mistake, i read 65 as 65%
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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08 Jul 2008, 08:06
durgesh79 wrote:
total number of people is T
61% of T is an integer --> T is a multiple of 100
31.5% of T is an interger --> T is multiple of 200

C+D = 8.5% * T = 65 + x

After here i looked at the answer choices and found 20. it is satifying both conditions...

continuing from C+D=8.5%*T => D = 8.5%T-65
Now for D to be +ve, T>= 800

For T= 800, D= 68-65=3 (not a valid choice)
For T= 1000, D = 85-65 = 20 which is (D).

if we go furhter,
For T= 1200, D = 102-65=37 (not a valid choice)

now the Question is, what if 37 was one of the choices? Any idea what should we do?
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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19 Mar 2015, 06:45
BG wrote:
Hi,Think that the ans is 20.
A and B together are 91.5%. This means that C and D together are 8,5%.Since it is given that C is 65 then the total number of people is at least 800. The next input is 1000 which gives 85, 65 for C and 20 for D

Could you please explain how you get that the total number at least 800???
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A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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Updated on: 17 Apr 2015, 11:42
2
earnit wrote:
nirimblf wrote:
A juice manufacturer organized taste-testing sessions featuring four brands of orange juice, A, B, C and D. All customers who participated told the organizer which variety they thought was the most similar to freshly-squeezed orange juice. 61% preferred brand A and exactly half as many preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?

(A) 1
(B) 8
(C) 14
(D) 20
(E) 27

Is there any other approach to this question which is easy to comprehend?

Hi earnit, the question can be solved without necessarily going into the values of T. In fact most of such PS questions can be simplified into expressions which would give you a pattern about the required values. The pattern can then be used to eliminate the option choices.

In this case, we know that C+D= 8.5% of T

We can write $$T = \frac{(65+D)*1000}{85}$$.

Hence, $$T= \frac{(65+D)*200}{17}$$ $$= \frac{(68+D -3)*200}{17}$$. Since 68 is a multiple of 17, for T to be an integer, (D -3 ) has to be a multiple of 17. So D has to be 3 greater than any multiple of 17. Only option which satisfies this condition is 20

Hope this helps!

Regards
Harsh

Originally posted by EgmatQuantExpert on 17 Apr 2015, 06:11.
Last edited by EgmatQuantExpert on 17 Apr 2015, 11:42, edited 1 time in total.
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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17 Apr 2015, 11:09
1
I hope in the expression it must be 8.5 not 85..

T=(65+D)∗100/85

Because if C+D=8.5% of T
then, C+D=8.5*T/100
Thus T=(65+D)∗100/8.5
But even here the multiple of 17 for 68 follows..
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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10 Aug 2015, 08:17
nirimblf wrote:
A juice manufacturer organized taste-testing sessions featuring four brands of orange juice, A, B, C and D. All customers who participated told the organizer which variety they thought was the most similar to freshly-squeezed orange juice. 61% preferred brand A and exactly half as many preferred brand B. Only 65 chose brand C. Which of the following could be the number of customers who preferred brand D?

(A) 1
(B) 8
(C) 14
(D) 20
(E) 27

Hi Bunuel,

I am getting C+ d = 8.5 % of total

As A = 61%
B= 30.5 %

so c+ d = 8.5% T.

But I got stuck here.

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A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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17 Aug 2015, 22:18
1
Hi there!

C + D = 8.5% of X (X=total number) . Given C = 65

After substituting and rearranging , we get :

D= (85/1000)X - 65.

Now, problem solving is all about getting the answer with minimum calculation. Options always play a significant role in this aspect.

If we carefully look into the options, we will figure that considering X=1000, we will get D=20. (Considering anyother value of X doesnt suffice any option).

Take away: Options are an important tool for reasoning and getting the correct answer. Keep an eye to this fact.
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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03 Oct 2016, 15:07
I set up an equation and plugged in the answers. I set the total as "T".
A=0.61T
B=30.5T
C=65
D= 20(plugged in from answer choice)

91.5T+85=100T
85=8.5T
T=1 or 100%
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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10 Oct 2016, 07:09
agree with what was said above
solved the same way...
61+30.5 = 91.5%
rest = 8.5%
total people x
85x/1000 = 65+D
x = (65+D)*1000/85
only 20 works.
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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08 Jul 2017, 02:01
Can anyone please tell why are we taking B = 1/2 A? If 61.5 % of the people preferred A then isnt it possible than there are people who also prefer brand B in this 61.5%?

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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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08 Jul 2017, 04:19
Sash143 wrote:
Can anyone please tell why are we taking B = 1/2 A? If 61.5 % of the people preferred A then isnt it possible than there are people who also prefer brand B in this 61.5%?

I think the trick is in the way it is worded.

61% preferred brand A and exactly half as many preferred brand B.

No, matter what 61.5% signifies, half of that number was opted by B. Half of that number translates to half the percentage. Hope its clear.
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Re: A juice manufacturer organized taste-testing sessions featuring four  [#permalink]

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08 Jul 2017, 04:55
Sash143 wrote:
Can anyone please tell why are we taking B = 1/2 A? If 61.5 % of the people preferred A then isnt it possible than there are people who also prefer brand B in this 61.5%?

All customers who participated told the organizer which variety they thought was the most similar to freshly-squeezed orange juice.

The above implies that each participant chose exactly one variety of juice, the one he/she thought was the most similar to freshly-squeezed orange juice.
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Re: A juice manufacturer organized taste-testing sessions featuring four   [#permalink] 08 Jul 2017, 04:55
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