chetan2u wrote:
It can be determined from the graph that the probability is greater than 0.98 that someone with a cold will have
Total probability = P(no symp) + P (exactly 1) + P (exactly 2) + P(exactly 3) + P (exactly 4)
We need to find probability that is greater than 0.98 , meaning almost 1. This implies that almost covers all the cases.
Acc. to options, we have Day 2 , Day 6 , Day 10
For Day 2 and Day 6,
Total probability = P(no symp) + P (exactly 1) + P (exactly 2) + P(exactly 3) + P (exactly 4)
Options given: one or fewer, one or more, two or fewer, exactly two
None of the options cover all the cases.
For Day 10,
Total probability = P(no symp) + P (exactly 1) + P (exactly 2)
In this case, two or fewer cover all the cases.
answer: two or fewer, Day 10