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Re: math problem [#permalink]
Yeah... just multiply out 6(x+3) and sum:

x^2 + 6x + 9 + 6x + 18 + 9 = 0

x^2 + 12x + 36 = 0

( x+6)(x+6) = 0

-6 is answer
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Re: math problem [#permalink]
Here's a slightly different approach.

You recognize that original equation has the form a^2+2ab+b^2=(a+b)^2
with a=(x+3) and b = 3.

Therefore the original equation can be written as

(x+3+3)^2=0 ===> x = - 6



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Re: math problem [#permalink]
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