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# Perm & Comm

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Manager
Joined: 29 May 2007
Posts: 97
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Kudos [?]: 2 [0], given: 0

Perm & Comm [#permalink]  12 Aug 2007, 11:58

There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction.
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?

A. 20

B. 25

C. 40

D. 60

E.125
Director
Joined: 01 May 2007
Posts: 794
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I'm thinking 20. My thought process was

red, red, red, blue, yellow.

so...

5! /(3!)(1!)(1!) = 20.

I might be way off though.
Manager
Joined: 07 Feb 2007
Posts: 54
Followers: 1

Kudos [?]: 0 [0], given: 0

jimmyjamesdonkey wrote:
I'm thinking 20. My thought process was

red, red, red, blue, yellow.

so...

5! /(3!)(1!)(1!) = 20.

I might be way off though.

Agree with jimmy's explanation and answer. What's the OA?
Director
Joined: 30 Jun 2007
Posts: 793
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Let A,B,C,D and E are filve parking slots:
A B C D E
R R R Y B

Anagram: RRRYB

A B C D E
R B Y R R

Anagram: RBYRR

Number of combinations = 5! / 3! 1! 1!
= 5 * 4
= 20

Intern
Joined: 07 Aug 2007
Posts: 7
Followers: 0

Kudos [?]: 0 [0], given: 0

5!/3!*1!*1!.

What's the OA?

Good question btw.
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