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# The number of North American children who are obese that is,

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Director
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The number of North American children who are obese that is, [#permalink]  11 May 2005, 14:47
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12. The number of North American children who are obeseâ€”that is, who have more body fat than do 85 percent of North American children their ageâ€”is steadily increasing, according to four major studies conducted over the past 15 years.

If the finding reported above is correct, it can be properly concluded that

(A) when four major studies all produce similar results, those studies must be accurate
(B) North American children have been progressively less physically active over the past 15 years
(C) the number of North American children who are not obese increased over the past 15 years
(D) over the past 15 years, the number of North American children who are underweight has declined
(E) the incidence of obesity in North American children tends to increase as the children grow older
Current Student
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[#permalink]  12 May 2005, 21:09
B. Used round-a-bout logic.
Manager
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[#permalink]  13 May 2005, 04:18
but B provides common knowledge. physical excercise is not in the text.

D maybe?
Current Student
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[#permalink]  13 May 2005, 05:42
Good point july05!

I agree. The answer should be D.

PS: Long live Uchenko!
Senior Manager
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[#permalink]  13 May 2005, 07:13
"D"
Good question, took me almost 3 mins to comprehend and arrive at the answer!

A, B, E are totally out of contest.

Its between C and D,

(C) the number of North American children who are not obese increased over the past 15 years
This means that even if number of children who are not obese increased, but the obese can still remain at same number. Does not lead to conclusion.

(D) over the past 15 years, the number of North American children who are underweight has declined

Correct. we can conclude that underweight have declined.
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Director
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All wrong ! The OA is C.
Director
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[#permalink]  14 May 2005, 15:41
Man, you should have posted OA earlier, I spent 1 hour last night trying to figure out why D was the right answer according to majority of people. (My original answer was C).
Underweight is not even defined in the argument.
Director
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Re: Answer [#permalink]  14 May 2005, 17:48
WinWinMBA wrote:
All wrong ! The OA is C.

WinWinMBA, Can you provide any explanations?
Director
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[#permalink]  14 May 2005, 18:00
arrange all the kids according to their weight, now make a cut at 85%, let's call obese 15% o and the rest no

then their ratio is o/no = 3/17, to keep the ratio constant if o is increased, you need to increase no (not obese) therefore C.
Director
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[#permalink]  15 May 2005, 02:52
sparky wrote:
arrange all the kids according to their weight, now make a cut at 85%, let's call obese 15% o and the rest no

then their ratio is o/no = 3/17, to keep the ratio constant if o is increased, you need to increase no (not obese) therefore C.

Thanks Sparky, The first time around I overlooked the fact that the ratio has to be constant.
Director
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[#permalink]  16 May 2005, 03:51
sparky wrote:
arrange all the kids according to their weight, now make a cut at 85%, let's call obese 15% o and the rest no

then their ratio is o/no = 3/17, to keep the ratio constant if o is increased, you need to increase no (not obese) therefore C.

Thanks sparky, good analysis.
[#permalink] 16 May 2005, 03:51
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# The number of North American children who are obese that is,

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