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The sum of the digits of a standard two-digit numeral is 9.

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The sum of the digits of a standard two-digit numeral is 9. [#permalink] New post 30 Jun 2004, 16:56
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The sum of the digits of a standard two-digit numeral is 9. if the digits are reversed, the numeral represents a numberthat is 45 less. What is the original numeral?
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 [#permalink] New post 30 Jun 2004, 17:39
let the number be xy.

its value = 10x+y
when digits are reversed ,value = 10y+x

given
1. x+y = 9
2. 10x+y = 10y+x +45 simplifies to x-y=5

solve
x=7, y=2 : the number is 72

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 [#permalink] New post 30 Jun 2004, 18:25
Same method as Ash. Wow, this problem bogged me for a while until I realized the subtlety of the 2nd sentence.
Sentence says: if the digits are reversed, the numeral represents a number that is 45 less
I misread that as: if the digits are reversed, the numeral represents a number that is less than 45 --> This would have given 81, 72 or 63!
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 [#permalink] New post 30 Jun 2004, 23:23
For small numbers like these (ie 2 digit numbers), the trial-and -error method works well...
you could fix the tens digit, put a unit's digit 5 more than that and check. The calculations are simple and the answer can be reached easily.

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  [#permalink] 30 Jun 2004, 23:23
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