Hi,

1) You have to find the

even (3 digit) numbers greater than 700, with non-zero digits as well as distict digits.

So, available digits would be (1 to 9)Even numbers starting with 7 = 1*7*4 = 28 (Hundredth digit is 7 - so, only 1 choice, unit digit can be (2, 4, 6, 8). Now tens digit will not be 7 & a digit chosen at units place - 7 possibilities)

Even numbers starting with 8 = 1*7*3 = 21

Even numbers starting with 9 = 1*7*4 = 28

Total numbers = 77

2) You have to find the

odd (3digit) numbers greater than 800, all distict digits.

Available digits would be (0 to 9)Odd numbers starting with 8 = 1*8*5 = 40 (Hundredth digit is 8 - so, only 1 choice. Unit digit can be (1, 3, 5, 7, 9). Now tens digit will not be 8 & a digit chosen at units place - 8 possibilities)

Odd numbers starting with 9 = 1*8*4 = 40 (Hundredth digit is 9 - so, only 1 choice. Unit digit can be (1, 3, 5, 7). Now tens digit will not be 9 & a digit chosen at units place - 8 possibilities)

Total numbers = 32

Let me know, if you need any further help on this.

Regards,

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