Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
25 Jun 2025, 23:55
Kudos
Bookmarks
sahitiyalavarthi
“Distinct non-zero digits” means the digits must all be different from each other and none of them can be 0. So, for example, 123 is fine, but 121 is not (repeated digit), and 120 is not (includes 0).
13 Oct 2025, 09:45
Kudos
Bookmarks
This is a classic counting problem where you need to juggle multiple constraints simultaneously. Let me walk you through how to approach this systematically.
Understanding What We Need:
We're looking for 3-digit numbers (let's call them ABC where A is hundreds, B is tens, C is units) that satisfy ALL of these:
The Key Insight:
Notice how A only has 3 possible values? That's your most restrictive constraint, so let's organize our counting around it. Here's what you need to see: when A is even (specifically 8), it affects how many choices we have for C!
Let's Count Case by Case:
Case 1: When A = 7
Case 2: When A = 8
Case 3: When A = 9
Final Count: \(28 + 21 + 28 = 77\)
Answer: E
The complete solution on Neuron reveals the systematic framework for identifying constraint hierarchies in any counting problem, plus time-saving techniques for recognizing similar patterns across different question types. You can check out the step-by-step solution on Neuron by e-GMAT to master the constraint-based counting approach systematically. You can also explore other GMAT official questions with detailed solutions on Neuron for structured practice here.
Hope this helps!
Understanding What We Need:
We're looking for 3-digit numbers (let's call them ABC where A is hundreds, B is tens, C is units) that satisfy ALL of these:
- Greater than 700, so A must be 7, 8, or 9
- Even numbers, so C must be 2, 4, 6, or 8
- All digits distinct (no repeats)
- All digits non-zero (only use 1-9)
The Key Insight:
Notice how A only has 3 possible values? That's your most restrictive constraint, so let's organize our counting around it. Here's what you need to see: when A is even (specifically 8), it affects how many choices we have for C!
Let's Count Case by Case:
Case 1: When A = 7
- C must be even and different from 7, so C can be: 2, 4, 6, or 8 → that's 4 choices
- B must be different from both 7 and whatever C is → from 9 digits, exclude 2 (A and C) → 7 choices
- Total: \(1 \times 7 \times 4 = 28\)
Case 2: When A = 8
- Here's the critical part: C must be even AND different from 8
- So C can only be: 2, 4, or 6 → that's just 3 choices (not 4!)
- B must be different from 8 and C → still 7 choices
- Total: \(1 \times 7 \times 3 = 21\)
Case 3: When A = 9
- C must be even and different from 9 → C can be: 2, 4, 6, or 8 → 4 choices
- B different from 9 and C → 7 choices
- Total: \(1 \times 7 \times 4 = 28\)
Final Count: \(28 + 21 + 28 = 77\)
Answer: E
The complete solution on Neuron reveals the systematic framework for identifying constraint hierarchies in any counting problem, plus time-saving techniques for recognizing similar patterns across different question types. You can check out the step-by-step solution on Neuron by e-GMAT to master the constraint-based counting approach systematically. You can also explore other GMAT official questions with detailed solutions on Neuron for structured practice here.
Hope this helps!
