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Kudos owned by the user


PrashantPonde received 171 Kudos for post If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?.

GiverPostDate
zoravarIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?01-Oct-2018
OmarJIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?29-Sep-2018
ndfan37If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?18-Sep-2018
jainanurag470If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?17-Sep-2018
Sappy12If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?08-Sep-2018
blight12If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?03-Sep-2018
ranjeeth666If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?08-Aug-2018
houston1980If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?08-Aug-2018
cdunton3If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?08-Aug-2018
pranitha21196If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?30-Jul-2018
adlihlIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?30-Jul-2018
hassu13If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?28-Jul-2018
kavyaguptaIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?23-Jul-2018
HisHoIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?07-Jul-2018
DeludedDuckIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?04-Jul-2018
wcha1990If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?02-Jul-2018
rishabh87If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?07-Jun-2018
ColonelRedIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?01-Jun-2018
sagnik104If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?24-Apr-2018
sudha8050If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?29-Oct-2017
workingfor2020If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?10-Sep-2017
satsurfsIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?13-Aug-2017
egghead2017If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?03-Jul-2017
DzjejniIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?01-Jul-2017
ktr1991If u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?02-May-2017
Pol DCIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?22-Apr-2017
MrtinhnvIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?27-Feb-2017
sananoorIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?21-Oct-2016
ChongHKIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?08-Oct-2016
ToludoIf u(u+v) <> 0 and u > 0 is 1/(u + v) < 1/u + v ?10-Sep-2016

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