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Bunuel received 1 Kudos for post If x ≠ 0, is (x^2 + 1)/x > y? (1) x = y (2) y > 0.

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ShwetaSingh1212If x ≠ 0, is (x^2 + 1)/x > y? (1) x = y (2) y > 028-Apr-2020

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