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(10000) ^100=? > A, (100) ^2* (100) ^100 >

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(10000) ^100=? > A, (100) ^2* (100) ^100 >  [#permalink] New post 21 Oct 2003, 03:33
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1. (10000) ^100=?
> A, (100) ^2* (100) ^100
> B, 100^200
> C, 10^400

2. 3^6X=8100, 3^ (X-1) =?
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 [#permalink] New post 21 Oct 2003, 10:44
Here's what I got:

Write 10,000 in terms of 10

10,000 = 10*10*10*10= 10^4
Then, you have (10^4)^100 to bring this number to the original statement. Multiply this out and you get 10^400
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 [#permalink] New post 22 Oct 2003, 14:52
I do not know if I am missing anything here.

For question 1: Both B and C seems to be correct

(10000)^100 = (100^2)^100 = 100^200.....CHOICE B

Similarly,

(10000)^100 = (10^4)^100 = 10^400.....CHOICE C

Question 2:

3^6x = 8100 => (3^3x)^2 = (+-90)^2 => 3^3x = +-90

Now 3^(x-1) = 3^x / 3 = +-90/3 = +-30
  [#permalink] 22 Oct 2003, 14:52
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(10000) ^100=? > A, (100) ^2* (100) ^100 >

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