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# (10000) ^100=? > A, (100) ^2* (100) ^100 >

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Manager
Joined: 27 Jul 2003
Posts: 124
Location: Singapore
Followers: 1

Kudos [?]: 10 [0], given: 0

(10000) ^100=? > A, (100) ^2* (100) ^100 >  [#permalink]  21 Oct 2003, 02:33
00:00

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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
1. (10000) ^100=?
> A, (100) ^2* (100) ^100
> B, 100^200
> C, 10^400

2. 3^6X=8100, 3^ (X-1) =?
Senior Manager
Joined: 07 Oct 2003
Posts: 358
Location: Manhattan
Followers: 2

Kudos [?]: 8 [0], given: 0

Here's what I got:

Write 10,000 in terms of 10

10,000 = 10*10*10*10= 10^4
Then, you have (10^4)^100 to bring this number to the original statement. Multiply this out and you get 10^400
Manager
Joined: 11 Mar 2003
Posts: 54
Location: Chicago
Followers: 1

Kudos [?]: 0 [0], given: 0

I do not know if I am missing anything here.

For question 1: Both B and C seems to be correct

(10000)^100 = (100^2)^100 = 100^200.....CHOICE B

Similarly,

(10000)^100 = (10^4)^100 = 10^400.....CHOICE C

Question 2:

3^6x = 8100 => (3^3x)^2 = (+-90)^2 => 3^3x = +-90

Now 3^(x-1) = 3^x / 3 = +-90/3 = +-30
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